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Registered Member #2938
Joined: Thu Jun 17 2010, 04:31AM
Location:
Posts: 1
Hello everyone, First I have to say I am not so educated about electronics and RF and all that but I am slowly learning. I was just thinking about something...maybe someone can help me out and explain somethings to me... Say you have a battery (let's say a 1.5 volt, 1aH one.) If it can produce 1 amp for one hour (minus some losses I guess) does that mean it will produce 2 amps at 1.5 volt for a half hour (minus some more losses), and 60 amps for one second (I suspect that the shorter it gets, the more losses but I don't really know) and on and on, so if you could make a really short pulse, say 100 ns, it could make a 10^7 amps pulse (because 1 ns is 10^9 seconds)?? ...mhh... 1) is it any clear? 2) does it work like that or not at all? 3) what would be needed to make that kind of effect? I guess a super fast switching transistor but it would have to be able to handle the 100 000 000 amps 1.5 volt 100 ns pulse (if that theory made any sense) 4) I mean, mathematically it makes some sense to my very untrained mind...that if you decrease the time you can increase the power...
any explanation would greatly de-mystify the whole thing to me.. thanks a lot
Registered Member #540
Joined: Mon Feb 19 2007, 07:49PM
Location: MIT
Posts: 969
Each source has an internal resistance which would limit the max amount of current you get. You will get a finite current if you completely short the battery because the internal resistance of it is dropping the full potential (it would get very hot). This works better with capacitors but even those have internal resistance and inductance which limits the maximum current spike you can get.
You might want to read though the electromagnetic projectiles forum for more info. There's also info about these high current pulses in the HvWiki under coil guns.
Registered Member #1792
Joined: Fri Oct 31 2008, 08:12PM
Location: University of California
Posts: 527
Also, each battery has an optimum discharge rate. The series resistance of the battery will convert a greater fraction of the battery's energy to heat at higher discharge rates (I^2*R), and there is probably battery chemistry stuff going on too, but if you discharge the battery faster than the optimal speed, then you will get less total energy out of the battery.
The energy capacity of the battery will usually be listed on the battery's datasheet (if you have one), and it will be listed on a graph versus discharge current. Though it will only be listed for "reasonable" currents, which can vary widely depending on the battery.
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Ultra-short pulse equals big amps?
