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Dividing the reading on an analog voltage meter

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HazzWold 1993
Sun May 30 2010, 11:01AM Print
HazzWold 1993 Registered Member #2563 Joined: Mon Dec 21 2009, 10:17AM
Location: Australia
Posts: 280
Is it possible? i know you can do it with analog amp meters but how would you make an analog voltage meter read a divided portion of that given load, eg. give it 500 and it read 100, or have it read 250.
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radiotech
Sun May 30 2010, 02:34PM
radiotech Registered Member #2463 Joined: Wed Nov 11 2009, 03:49AM
Location:
Posts: 1546
This is for a DC voltmeter: *

Measure its resistance. Divide that resistance by the full scale reading in volts of the meter. Now you have the ohms per volt value.

Example 100 volts full scale , 50,000 ohms = 500 ohms per volt.

If you need the meter to read 500 volts full scale, multiply 500 volts by 500 ohms per volt . that would be 250,000 ohms.

your meter already has 50,000 ohms resistance. You add a 200,000 ohm ressistor in series. The meter will now read 0-500 volts.


double check. 250,000 ohms / 500 volts = 500 ohms per volt.

*an AC voltmeter multiplier resistor needs a different method to calc.
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IamSmooth
Sun May 30 2010, 07:34PM
IamSmooth Registered Member #190 Joined: Fri Feb 17 2006, 12:00AM
Location:
Posts: 1567
I think he wanted to drop the scale down and not up.

You probably have to take it apart and take out the resistor and replace it with one of the appropriate resistance. You will need to know the current needed for a full-scale deflection without the series resistor. Then, you need to determine what value of R will turn your desired full-scale voltage into that amount of current.
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radiotech
Sun May 30 2010, 08:03PM
radiotech Registered Member #2463 Joined: Wed Nov 11 2009, 03:49AM
Location:
Posts: 1546
That would require determining the amp-ohms of the meter coil at full scale.
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