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Here's a thought experment for you. Take a magnetron that's creates a 100khz mw feild and take a coil of wire that resonates to 100khz. put a metal shell around the coil form and put the beam in the box. when the magnetron is turned on....
My reson why i don't think this will go on fire= put a fork in a mw. what will happen? A. the metal will heat up and it WONT SPARK. So the electrons are induced in the metal and heat it up. ( i think it's called eddy currents) if the things are tuned to each other, my theory is = more electrons will flow through the metal, and it will work kind of like a transformer, using microwaves instead of magnetic fields.
Registered Member #543
Joined: Tue Feb 20 2007, 04:26PM
Location: UK
Posts: 4992
Setting aside the fact that magnetrons can not be made to operate at Low Frequency as you suggest, and moving on to what I think you are trying to get at:
A tuned resonator irradiated with microwaves by an oven magnetron will develop voltage nodes along its length. For simplicity's sake, let us imagine a resonator one half wavelength long which would be nominally 61mm for excitation by a 2.45GHz magnetron - but in practice about 90 - 95% of this length, because of the the Velocity Factor - the ratio of the Velocity of an EM wave in the conductor to its Velocity in Free Space.
So we have a copper rod about 55mm long (the precise length for resonance must be determined empirically in each case, because of many small variables) resonating in synchrony with the magnetron at 2.45MHz, and we find that at the precise point of maximum resonance the production of Standing Waves leads to the formation of voltage nodes at both ends of the rod, and a null in the centre.
With sufficient power, these high voltage nodes will most certainly flash over.
If you're keen to get on in electronics, you have no choice but to start your studies at the very beginning with a thorough grasp of such things as basic magnetism, electromagnetism, electrostatics, Ohm's Law, and the basic properties of resistors, capacitors and inductors in DC and AC circuits. Electronics - like all sciences - is built like a tower block, so without sound foundations you will have nothing to build on. Each floor is built on top of the floor below, and you cannot make confident and reliable progress in knowledge till each floor is strong enough to take the weight of the next set of ideas to be built upon it. You cannot build a second floor without the first, and to attempt to do so is a half-baked pie without a pie stand, a Pie in the Sky, and an embarrassment . We all had to start at the beginning.
don't worry I've learned electronics science i was 5. I've tackled most of what you've said, but I'm just learning about the wierd and wonderful world of rf.8-)
thanks for the support, my half baked pie ideas, so to say flawed "thought experments' are thought when i'm in the john. sorry if i using wrong ideas
Thanks, Paul
PS. what is the amount of power required for the flash over? is this more than the least amount of power required for the mag to operate? what if you used power levels lower than the flash over point?:-?
Registered Member #1792
Joined: Fri Oct 31 2008, 08:12PM
Location: University of California
Posts: 527
It's just like a tank circuit being driven at its resonant frequency, the stored energy in the resonator will keep rising until the power losses match the power input. Since the quality factor (ratio of stored to dissipated energy per cycle) of the proposed resonator is likely to be quite high, it probably will not take much power to reach flashover. If your input power was low enough that voltage rise was limited by resonator losses rather than flashover, then it would simply resonate with voltage and current standing waves like an antenna in a receiver.
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Directing a microwave field on a tuned piece of metal?
