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4hv.org :: Forums :: General Science and Electronics
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inverter snubber capacitors

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IamSmooth
Sun May 16 2010, 06:22AM Print
IamSmooth Registered Member #190 Joined: Fri Feb 17 2006, 12:00AM
Location:
Posts: 1567
Using this schematic as a reference, Link2

what is the effect of increasing the value of C4 and C5? How does this change the behavior of the circuit, or does it not significantly affect it?
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kell
Sun May 16 2010, 03:17PM
kell Registered Member #142 Joined: Sat Feb 11 2006, 01:19PM
Location:
Posts: 102
What about that circuit do you understand, and what do you not understand? Where did you find it?
Did it occur to you that you might want to provide some context? Are you looking for a deeper understanding of the way a half-bridge driver works?
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Steve Conner
Sun May 16 2010, 03:31PM
Steve Conner Registered Member #30 Joined: Fri Feb 03 2006, 10:52AM
Location: Glasgow, Scotland
Posts: 6706
Those aren't snubber capacitors, they're just the usual RF bypass caps. Notice they're not actually connected across the MOSFETs, just across the DC bus.

He could have left them out and returned the work circuit straight to the negative terminal of the DC bus cap, but maybe he wanted isolation for safety.
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radiotech
Sun May 16 2010, 04:34PM
radiotech Registered Member #2463 Joined: Wed Nov 11 2009, 03:49AM
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Posts: 1546
C4, C5 in parallel is 2 ufd. C9 is in series. The work coil is in series with 0.67 ufd effectively. If C10 resonates the work coil, then the
load (heat) divided by the voltage across the coil would be the amps that are limited by the reactance of 0.67 ufd. Of course Gnd and + are assumed to be a constant voltage source with zero impedance,but it probably isnt, so messing with the magic that makes the thing work could be interesting.

Reduce the 0.67ufd and the thing would produce less heat.

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IamSmooth
Mon May 17 2010, 01:38AM
IamSmooth Registered Member #190 Joined: Fri Feb 17 2006, 12:00AM
Location:
Posts: 1567
Steve McConner wrote ...

Those aren't snubber capacitors, they're just the usual RF bypass caps. Notice they're not actually connected across the MOSFETs, just across the DC bus.

He could have left them out and returned the work circuit straight to the negative terminal of the DC bus cap, but maybe he wanted isolation for safety.

And now it gets interesting...

This is exactly what I would have thought. Instead of the potential on the transformer being Vc and Vc/2, it is now Vc and 0. However, it does not work. If I take the lead going to the capacitor divider between C4 and C5 and connect it to ground, I don't get a clean square wave and the current just shoots up as I increase the supply voltage. I don't understand why the divider is necessary.
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radiotech
Mon May 17 2010, 04:31AM
radiotech Registered Member #2463 Joined: Wed Nov 11 2009, 03:49AM
Location:
Posts: 1546
" If I take the lead going to the capacitor divider between C4 and C5 "

What do you think these capacitors divide? they are connected across a DC source blocked by 2500 ufd.

Once the coil current passes through a capacitor, it become 'alternating current', whatever waveform, sine, square or something between, its still AC.
and C4, C5, and C9 ( 0.67ufd) are part of tuned circuit with L1.

Change that value of capacitance--it changes the tuning. By grounding the low end of the tank 0.67 was changed to 1ufd,
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Steve Conner
Mon May 17 2010, 08:31AM
Steve Conner Registered Member #30 Joined: Fri Feb 03 2006, 10:52AM
Location: Glasgow, Scotland
Posts: 6706
Maybe as Radiotech says, the capacitors are small enough that they provide enough reactance to mess with the tuning. You might need to retune the frequency if you remove them, or make C9 smaller to compensate.

Or maybe your C9 is shorted, so when you remove them there's no DC blocking any more.

Also, if C4/C5 are mounted near to the MOSFETs they are helping to clean up the DC bus. So even if you don't return the work circuit to the centre tap of them, maybe you shouldn't remove them altogether.
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