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Registered Member #190
Joined: Fri Feb 17 2006, 12:00AM
Location:
Posts: 1567
I need to filter a PWM (2000hz) into a clean DC signal. I use a passive RC filter (R = 1k, C = 470uf). I find that the higher I go on C the cleaner the DC, but the longer the RC constant. This long RC constant is undesirable.
The DC output controls a VCO. I am finding that the microprocessor's feedback is delayed too long if I want a really clean DC signal. What can I do to get the cleanest DC out of a PWM, but have a short time constant? Would an active filter be a better choice? Attenuation of the signal is not a problem, here.
Registered Member #103
Joined: Thu Feb 09 2006, 08:16PM
Location: Derby, UK
Posts: 845
You can cascade several RC filters, to improve the time constant whilst getting a good filter overall. Try a 3 pole RC first, roughly doubling the resistor value each stage, you could try: pwm > 4k7/22n > 10k/47n > 22k/100n > output. This is what I do to make cheap DACs using the PWM output from a microcontroller.
Registered Member #1667
Joined: Sat Aug 30 2008, 09:57PM
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Posts: 374
If you don't mind building some extra circuity, you could use a low order RC filter, followed by a synchronous sample&hold circuit that captures the filtered level at a given phase of the pwm cycle. The output would be a stable level with a few cycles for settling (some milliseconds). Changes to the PWM cycle would result in voltage steps. You can smooth them out with another lower order filter.
If that's too much work for you, get a I²C DAC like the MCP4725A0T-E/CH which is really simple to use, fast and cheap.
Registered Member #1232
Joined: Wed Jan 16 2008, 10:53PM
Location: Doon tha Toon!
Posts: 881
First of all, push the PWM frequency as high as you can whilst still maintaining the required resolution. This makes the filtering that follows easier because it moves the ripple frequency higher and further away from the low frequency information that you want to preserve.
For many applications a simple first-order lowpass RC filter (one R and one C) will be enough. But if you cant find a combination that gives a satisfactory compromise between adequate supression of the switching carrier frequency and sufficiently fast resposne to changes of duty-ratio then you either need to increase the PWM carrier frequency or use a better reconstruction filter.
As Avalanche said you can use more elaborate passive filters, or something like a butterworth or chebychev active filter using an op-amp to produce a more powerful filter with a steeper transition band.
In the most demanding of circumstances you could even use an elliptic "Cauer" filter where the pass-band is very flat, then it transitions very rapidly into heavy attenuation at the high frequency end. If you design it right you can even place one of the zeros of the elliptic filter response right on top of the PWM switching frequency. This gives you infinite suppression of the carrier frequency, at least in theory!
Registered Member #190
Joined: Fri Feb 17 2006, 12:00AM
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Posts: 1567
Thanks for the replies.
With regard to 2nd and 3rd order RC filters:
I did some Bode plots and can see how each tier will add another -3db/decade. If I have two 22uf/1k filters I will get twice the attenuation. My question is how does this affect the RC time constant? Is it additive?
Registered Member #2463
Joined: Wed Nov 11 2009, 03:49AM
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Posts: 1546
IamSmooth wrote "I need to filter a PWM (2000hz) into a clean DC signal"
Could this question be asked like this: The signal is DC pulses which repeat every 500 uSec and a DC voltage proportional to the pulse width , averaged over some time period , greater than 500 uSec, is needed. How long do you want this time period to be?
Registered Member #1792
Joined: Fri Oct 31 2008, 08:12PM
Location: University of California
Posts: 527
The more effective your low pass filter is, the longer your risetime is going to be because a fast risetime must contain high frequency content.
edit: I think time constants add more or less like resistors in parallel: 1/t_tot = 1/t1 + 1/t2 + ... edit2: That makes no sense, that would reduce your total time constant. But as I recall they add but it's less than t1 + t2 by some amount.
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