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Registered Member #1430
Joined: Sun Apr 06 2008, 11:12AM
Location: Ã…rhus, Denmark
Posts: 102
I'm building a UV exposure box for making PCBs, i'm building it on a stripboard and i'm gonna make it 7 by 7 LEDs. now, how would i go about calculating the 7 required resistors for powering the LED's in 7 strings of 7 LEDs connected in series? i'm planning on using a 230 to 2*12 transformer to get about 24 volts.
EDIT: i didn't think this through AT ALL. i have decided to just go with a 6 by 6 board.
would i be able to run this with a 10v 850mA transformer driving 12 strings of 3 LEDs in serial? 3 LEDs with a forward voltage of 3.3v each = 9.9v per string. 6*6 LEDs with a forward current of about 20Ma = 720mA total. right?
Registered Member #56
Joined: Thu Feb 09 2006, 05:02AM
Location: Southern Califorina, USA
Posts: 2445
The 3 led strings would probably work, but you really need a some kind of resistor between the LEDs and the transformer, as the LEDs heat up the voltage drop changes slightly, which the resistor can help account for. If you have as 12v regulated supply (like a computer charger that puts out about 12v) around somewhere it would be ideal, you could add a 100 ohm resistor in series with each of the 3 led strings and maintain reasonable efficiency.
Also keep in mind that a transformer (as opposed to a regulated supply of some kind, like a smps supply) is not going to put out exactly 12.0v, but depending on the load, input voltage, etc, will put out a voltage of about 12v. Also if your transformer is not already rectified, you will need to do that which will further drop the available voltage.
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