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Registered Member #190
Joined: Fri Feb 17 2006, 12:00AM
Location:
Posts: 1567
I have searched some web pages and found things like this:
I have 18g wire wrapped in a bundle embedded in fiberglass. The top and bottom of the coil is just barely covered with fiberglass resin/marble dust and the center of the coil is hollow (no resin, just air).
The link I have show is very conservative. Anyone have an idea how much current I can put in without burning out the coil? I may have to just start putting in current myself and measure the temperature with an IR thermometer.
Registered Member #543
Joined: Tue Feb 20 2007, 04:26PM
Location: UK
Posts: 4992
Tf = Ti + [q / (m x Cg)]
Tf is the temperature increase after 1 second Ti the initial temperature q is the energy in Joules, m is the total conductive mass of your wire in grams Cg is the specific heat of copper (0.385)
The final termperature will be reached with thermal equilibrium between your coil's resistive dissipation, and the heat lost through conduction, convection and radiation through your insulating material.
Registered Member #142
Joined: Sat Feb 11 2006, 01:19PM
Location:
Posts: 102
The chassis wiring and transmission line current limits on that website won't apply to a coil embedded in fiberglass. Here's a discussion forum for people that build wind turbines, and some of the people on the board have a lot of experience building coils similar to yours, embedded in materials such as epoxy or fiberglass. check out
Registered Member #30
Joined: Fri Feb 03 2006, 10:52AM
Location: Glasgow, Scotland
Posts: 6706
I'd check out guidelines for current density in transformer windings, these are probably more applicable. I seem to remember some simple rule of thumb that just recommends so many amps per square inch of copper cross-section. 400, or 750 or something.
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Wire size and current capacity
