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Inductance with a fast pulsed circuit

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likewhat
Fri Dec 26 2008, 12:51AM Print
likewhat Account deactivated by user request on 6/11/2009.
Registered Member #1071 Joined: Fri Oct 19 2007, 02:13AM
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Posts: 44
I thought I would post this as a story about inductance. The goal was to build a small pulser that put out 10 kA with a rise time of about 100 ns with a charge voltage of less than 20 kV.

So the components were a 100kV 80 nF capacitor with 20 nH inductance and a spark gap switch that is triggered by dropping the air pressure from 20 psi to atmospheric. Initially I connected the capacitor to the switch with a piece of 60 kV floppy HV cable about 6 inches long then I went through a 5 ohm resistor to a ground strap that was about 4 inches long back to the other side of the capacitor. I was using a Northstar HV probe that is 80 MHz bandwidth I think.

So withj 10 kV charge the risetime with the above described setup was about 300 ns and the peak current was around 1 kA. The peak voltage was around 5 kV so the load was approximately matched. Ok so what this tells me is that the pulser impedance is about 5 ohms, which must be pretty much entirely inductive.

So, that was an utter failure.

This was then rebuilt by using a flat piece of copper that was about 10 cm wide from the positive terminal of the capacitor about 2 inches long to the switch, then to the same 5 ohm resistor, then another flat piece of copper 10 cm wide about 8 inches long to the ground of the capacitor.

At 10 kV charge this time there was 8 kV across the resistor. From a simple voltage divider circuit you can figure that the driver impedance must be about 1.25 ohms. So, with an ~1.25 ohm resistor this device put out about 4 kA peak current and the risetime was about 120 ns.

So the reduction in inductance by using large flat connections that ran parallel to each other allowed the impedance to be dropped by a factor of 4.

This was then rebuilt with a 220nF capacitor, still with 20 nH inductance and it put out about 7 kA with a slightly slower risetime of about 170 ns because of the increased capacitance (due to the rise time going like (LC)^.5, because risetime is something like 1/(1/4*frequency)). At 20 kV charge this will put out over 10 kA, the rise time is longer than I wanted, but it may be possible to speed it up a little by putting it into an overmatched load (at the expense of current).

My goal here was to give an example of how an inductance change can vastly change the behavior of a circuit that is fast. If there are any questions or if something wasnt clear let me know.

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