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Forums
4hv.org :: Forums :: Electromagnetic Projectile Accelerators
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Flyback transformers

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Camel
Thu Oct 09 2008, 11:28AM Print
Camel Registered Member #1694 Joined: Sat Sept 13 2008, 09:13AM
Location: Australia
Posts: 108
Hey all,
I have a flyback transformer out of an old monitor. Its pretty big and it would probably put out a much higher voltage than I need. So I thought I'd ask . . . has anyone made their own transformers? Is it worth doing?
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Proud Mary
Thu Oct 09 2008, 11:45AM
Proud Mary Registered Member #543 Joined: Tue Feb 20 2007, 04:26PM
Location: UK
Posts: 4992
Why not just run it at a lower input voltage?
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Camel
Thu Oct 09 2008, 12:10PM
Camel Registered Member #1694 Joined: Sat Sept 13 2008, 09:13AM
Location: Australia
Posts: 108
Mmmm . . . I'm still trying to learn how all this works.

I thought the output voltage would be determined by how quickly the current to the coil is changed, not so much by the input voltage. Am I wrong? :p
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Coronafix
Thu Oct 09 2008, 12:33PM
Coronafix Registered Member #160 Joined: Mon Feb 13 2006, 02:07AM
Location: Melbourne, Australia
Posts: 938
Voltage is proportional to number of turns. Vp/Vs=np/ns.
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Dr. Slack
Thu Oct 09 2008, 01:16PM
Dr. Slack Registered Member #72 Joined: Thu Feb 09 2006, 08:29AM
Location: UK St. Albans
Posts: 1659
The output voltage is determined by the rate of change of current, but the question is, what determines the rate of change of current.

If you are running it as a transformer, then the input voltage determines the rate of current change (into the inductance of the core) which determines the output voltage.

If OTOH you are running it as a flyback, then when the input current is interrupted, the charge (current = d(charge)/dt) builds up a very large voltage very quickly. How large depends on how fast the current has to fall. In an ignition coil, there is a capacitor across the opening switch contacts to allow the current to continue flowing as it charges the cap, which defines the rate of voltage rise. In a TV flyback used to draw an arc, the voltage rises as it's only the stray capacitances that absorb the current, so they charge very quickly, until the secondary gap breaks down to allow current to contnue to flow, which limits the voltage. If you're charging a capacitor, then the voltage in the strays rises until it overcomes the output capacitor voltage + N output diode drops, then the current flows into the load capacitor. If nothing breaks down, then the charge has been safely absorbed by the stray capacitance of the secondary.

You can also limit the output voltage of an unloaded flyback by limiting the input current before break (limiting the stored energy), or by limiting the primary voltage after break (with zeners, or diodes into a load)
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