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4hv.org :: Forums :: High Voltage
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Joule's from Marx Gen.

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GluD
Mon Aug 04 2008, 08:19PM Print
GluD Registered Member #1221 Joined: Wed Jan 09 2008, 06:17PM
Location: Odense, Denmark
Posts: 196
Hello

I was just sort of wondering how i am suposed to calculate the amount of joule's a marx generator can spit out ?

I've successfully built a marx gen. with four 1nf capacitors rated for 15kV, and it makes quite abit of noise, in the form of "bang" sounds, when it fires. So i started to wonder how to calculate the joule's, because i supose there must be a few since it makes all that noise.

Its no big deal but I'd like to know anyways.

Thank you very much indeed.
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Shaun
Mon Aug 04 2008, 09:50PM
Shaun Registered Member #690 Joined: Tue May 08 2007, 03:47AM
Location: New Jersey, USA
Posts: 616
It's just the total energy stored in all your capacitors:

4*(.5*.000000001F*15000V^2) =.45J

Assuming all your caps charge to 15kV
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Steve Ward
Tue Aug 05 2008, 04:51PM
Steve Ward Registered Member #146 Joined: Sun Feb 12 2006, 04:21AM
Location: Austin Tx
Posts: 1055
Yep, but dont forget that some of that energy is lost in your spark gaps, so not all of it makes it to the main discharge. But still, a good portion does, and all of those spark gaps still contribute to light and sound production.
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Hon1nbo
Tue Aug 05 2008, 05:20PM
Hon1nbo Registered Member #902 Joined: Sun Jul 15 2007, 08:17PM
Location: Pacific Northwest USA
Posts: 1042
also don't forget other losses, like your charging resistors (unless you are already blocking current flow, or you are having it discharge immediately after the the charge by using a smaller first spark gap).
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HV Enthusiast
Tue Aug 05 2008, 06:29PM
HV Enthusiast Registered Member #15 Joined: Thu Feb 02 2006, 01:11PM
Location:
Posts: 3068
DaJJHman wrote ...

also don't forget other losses, like your charging resistors (unless you are already blocking current flow, or you are having it discharge immediately after the the charge by using a smaller first spark gap).

Charging resistors will have little effect on energy loss during a discharge. During a discharge, the capacitors are charged up to some voltage and the impedance through the spark gaps to the output is magnitudes less than the impedance of the charge resistors.

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GluD
Tue Aug 05 2008, 07:00PM
GluD Registered Member #1221 Joined: Wed Jan 09 2008, 06:17PM
Location: Odense, Denmark
Posts: 196
I see, 0.45 joule sure aint as much as it sounds from those bangs.
Just as a side note, you got any idea of how many % joule is lost in the spark gab's, just a rough guess, perhaps?

Thank you very much for your kind and indeed very usefull answers. *bows*
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Shaun
Tue Aug 05 2008, 09:35PM
Shaun Registered Member #690 Joined: Tue May 08 2007, 03:47AM
Location: New Jersey, USA
Posts: 616
For percentage of energy lost in the gaps, I would think it would be equal to the % of the total arc length that the gaps make up.

For example, if you have a 20mm output discharge and four 5mm sparkgaps, then the gaps would be dissipating half the energy.
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Hon1nbo
Wed Aug 06 2008, 12:29AM
Hon1nbo Registered Member #902 Joined: Sun Jul 15 2007, 08:17PM
Location: Pacific Northwest USA
Posts: 1042
Dr. GigaVolt wrote ...

DaJJHman wrote ...

also don't forget other losses, like your charging resistors (unless you are already blocking current flow, or you are having it discharge immediately after the the charge by using a smaller first spark gap).

Charging resistors will have little effect on energy loss during a discharge. During a discharge, the capacitors are charged up to some voltage and the impedance through the spark gaps to the output is magnitudes less than the impedance of the charge resistors.



I meant before the discharge, therefore the caps have a lower charge that the theoretical voltage... I did not expect it to be an issue, but I have seen marx gens that had that problem, just making sure he does not make it.... sorry I kinda worded it funny...
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