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Registered Member #152
Joined: Sun Feb 12 2006, 03:36PM
Location: Czech Rep.
Posts: 3384
So after playing with all these arcs, I came up with a formula for calculating approximate maximum arc length that can be drawn from AC high voltage power supply/transformer:
L-maximum arc length in centimeters, current is in Amps [this is short circuit current!], voltage in kV:
L = U * sqrt(I) * 4
Conditions: -High voltage power supply 50/60Hz (might be *very little* bit longer for DC) -Inductively current limited -Arcs are drawn out vertically -Current must be >0.05A (otherwise the arc starts extinguishing between the halfwave periods and can be drawn out less).
Edit: Maybe this is better suited for the High Voltage section.
Registered Member #396
Joined: Wed Apr 19 2006, 12:55AM
Location: Pittsburgh, PA
Posts: 176
Interesting, but did I miss what "U" is in the equation? Something with atmospheric pressure? EDIT - HA I knew it was something simple, yes, I"m sure potential has something to do with spark length . . . its pretty late here . . .
I'd be interested to know how exactly you approached this by experimentation (not doubting you at all and thats not meant to sound sarcastic). Just plotting data points? It seems like it would take a while but Im glad someone actually did it instead of using the old "1mm=1kv"
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Electric arc length formula
