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4hv.org :: Forums :: General Science and Electronics
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Resonant voltage rise?

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Dr. Dark Current
Thu Jan 17 2008, 06:03PM Print
Dr. Dark Current Registered Member #152 Joined: Sun Feb 12 2006, 03:36PM
Location: Czech Rep.
Posts: 3384
Lets say I have a series LC circuit with resistance R in series with it. Is there a formula to calculate the resonant voltage rise of this circuit when excited at a given frequency?



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Marko
Thu Jan 17 2008, 07:55PM
Marko Registered Member #89 Joined: Thu Feb 09 2006, 02:40PM
Location: Zadar, Croatia
Posts: 3145
Voltage rise in a series RLC will be UR*Q, and Q factor is calculated by
Q=1/R*sqrt(L/C).

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Dr. Dark Current
Thu Jan 17 2008, 09:11PM
Dr. Dark Current Registered Member #152 Joined: Sun Feb 12 2006, 03:36PM
Location: Czech Rep.
Posts: 3384
Thanks, but this is just at the resonant frequency. Is there any formula that will tell me the voltage rise/Q factor at any frequency?
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Hazmatt_(The Underdog)
Fri Jan 18 2008, 12:42AM
Hazmatt_(The Underdog) Registered Member #135 Joined: Sat Feb 11 2006, 12:06AM
Location: Anywhere is fine
Posts: 1735
L = 2pi F XL
C = 1/ (2pi F Xc)

little extrapolation;

so L/C = 2pi F XL * 2pi F Xc = 4 pi^2 F^2 XL Xc

so Q = 1/R * sqrt( 4 pi^2 F^2 Xc XL)

or Q = 2piF/R *sqrt(Xc XL)

woops, heh, corrected, and I left the pi alone so you can see it better. I was trying to show that I pulled the 2piF out of the root. Didn't mean to make the equation wrong.
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Steve Conner
Fri Jan 18 2008, 10:30AM
Steve Conner Registered Member #30 Joined: Fri Feb 03 2006, 10:52AM
Location: Glasgow, Scotland
Posts: 6706
Yes, just substitute the values of Q and f0 you calculated into the transfer function of a second-order bandpass system, replace all the s (Laplace operator) for j*omega, square the whole mess, and you have the response as a function of frequency.

I found a Google Book that shows the method:
Link2
though it solves for the voltage across the resistor, which is probably not what you want.

Hazmatt's calculation looks wrong. :/
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