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Registered Member #162
Joined: Mon Feb 13 2006, 10:25AM
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Imagine the 240 Vrms with two 60uF capacitors as 120 Vrms with 120 uF in series. So the circuit becomes 120 Vac - capacitor - diode(s) - resistor - Neutral
Think of it as Neutral - Resistor - Diode(s) - capacitor - 120 Vac
a typical half-wave rectifier charging a capacitor
The capacitor will charge to almost 170 Vdc then no more current will flow. there will briefly be voltage across the resistor as the capacitor(s) charge, then no more.
The actual voltage at the junction of the capacitors will be 120 Vrms with a -170 Vdc offset On a 'scope that would look like a sinewave with the positive peaks just above 0 V (due to the diode(s) drop )
To make it work you need a full-wave (bridge) rectifier on the output of the capacitors.
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Mains Conn cted capacitor voltage divider driven a load
