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4hv.org :: Forums :: General Science and Electronics
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Air gap calculations

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Ben Solon
Fri Jul 13 2012, 03:54AM Print
Ben Solon Registered Member #3900 Joined: Thu May 19 2011, 08:28PM
Location:
Posts: 600
I am swapping out the ferrites in my boost converter to up the power a bit. My question is how leakage can be factored into the minimum turns formula to get the minimum number of turns on a 153mm^2 Ae core handling 170v for 30uS. I havnt found any sources that even go into air gaps let alone the calculations, so the biggest thing is to find some data on the subject.
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Sulaiman
Fri Jul 13 2012, 05:12AM
Sulaiman Registered Member #162 Joined: Mon Feb 13 2006, 10:25AM
Location: United Kingdom
Posts: 3140
You can use simple formlas such as;
Change in Flux = Integral (volt.seconds) = (170V/N)x30E-6 = 5.1/N mV.s = 5.1/N mWb
Flux Density = Flux/Area = 5.1 mWb/(N.153E-6) = 33.333/N Tesla
So, if you want your peak flux density to change by say 0.1 T (1,000 gauss)
0.1 = 33.333/N .... N = 333.33 turns
To decide on the airgap you must choose what inductance you want
which is determined by what change in current you want per cycle
based on operating frequency, duty cycle and power output.
Will this be a continuous-mode or discontinuous-mode boost converter?

lots of design info. at Fair-Rite, Magnetics inc., epcos (ferrite manufacturers websites) etc.
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Steve Conner
Fri Jul 13 2012, 06:53AM
Steve Conner Registered Member #30 Joined: Fri Feb 03 2006, 10:52AM
Location: Glasgow, Scotland
Posts: 6706
To a first approximation, the air gap doesn't change the volt-second capacity of the core, so the minimum number of turns is the same as for the ungapped case.

Explanation: The air gap increases the amp-turns for saturation, but it also reduces the inductance in the same proportion.

An air gap increases the energy storage capacity of the core, as this is 0.5*L*I^2. If we double the current rating and halve the inductance, the energy goes up by a factor of 2.
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Ben Solon
Fri Jul 13 2012, 12:51PM
Ben Solon Registered Member #3900 Joined: Thu May 19 2011, 08:28PM
Location:
Posts: 600
I still don't quite get it. Sulaiman, I get your calculations, but this applies to any ferrite gapped or ungapped doesn't it? And steve, I understand that, but I really don't care about energy storage as long as I don't saturate the core wink I have some ferrite u cores that i will put some turns on(~minimum + a few). Then I will increase the gap until it can withstand the 17A average, 23A peak I will be putting through it. My question is how I can calculate how far. And also, because the vt handling doesn't change, the minimum turns is still given by s-man's formula or the other ferrite b=vt/aeb one correct?
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Pinky's Brain
Fri Jul 13 2012, 02:58PM
Pinky's Brain Registered Member #2901 Joined: Thu Jun 03 2010, 01:25PM
Location:
Posts: 837
Here is an article for a discontinuous flyback which runs through calculations for pretty much the same thing you need (except you don't use the flyback phase) :
Link2

In addition to Sulaiman's formula it has a formula for L given the air gap and turns, and the L you want is V*T/I ... so that gives you the air gap.
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Ben Solon
Sun Jul 15 2012, 02:22AM
Ben Solon Registered Member #3900 Joined: Thu May 19 2011, 08:28PM
Location:
Posts: 600
Thanks, although I am using continuous mode operation, that site has a similar page for that type of operation.
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