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Registered Member #3900
Joined: Thu May 19 2011, 08:28PM
Location:
Posts: 600
is the datasheet of an inverter i have too many of. on page 4 there is the typical rc inverter oscillator schematic, but the formula for calculating t1, t2 and frequency are a bit unclear to me.
RC i assume is in ohms and farads. i don't know what l and n are. i know what vdd is and vt+/vt- are the trigger levels.
Registered Member #1792
Joined: Fri Oct 31 2008, 08:12PM
Location: University of California
Posts: 527
I think it's actually supposed to be together, "ln" (ell enn) as in the natural logarithm as in base e logarithm.
Since the voltage of a capacitor charging from a constant voltage through a resistor is exponential it makes sense when you solve for a time you have a natural log in there somewhere, since ln(e^x)=x.
Registered Member #3900
Joined: Thu May 19 2011, 08:28PM
Location:
Posts: 600
uhh.. this is why i need to be in higher level math classes... i know little about logarithms. taking a shot in the dark here, if i where to put this into my graphing calculator, it would look like this: R*C*ln(vt+/vt-) right? i just took out my ti-84 plus and noticed a "ln" button. i will do some calculations and see if they match up to real life experimental data.
Registered Member #1792
Joined: Fri Oct 31 2008, 08:12PM
Location: University of California
Posts: 527
Yep, that's what it will look like in your calculator ben.
Logarithms are the inverse of power operations. Logs always have a base, just "log" without specifying a base is assumed to be either base 'e' or base 10. If log10(x)=y that means 10^y=x, and thus log10(10^y)=y. For natural log, just replace 10 with e. e is a funny transcendental number (2.718281828...) which pops up in numerous useful places in math, including the fact that the derivative of e^x equals itself.
Since the voltage on a capacitor in an RC circuit tends to take the forms similar to V=e^(t/(R*C)), when you solve for time you'll get t=R*C*ln(V) because that ln is the function that undoes the exponent of e.
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