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Registered Member #2899
Joined: Wed Jun 02 2010, 06:31PM
Location: Deinze, Belgium
Posts: 255
I have 6 diodes 12 kVolt and 6 capacitors 1.6 kV. I assume I can make a cockroft walton 6 X multiplier, but what is the maximum ac I can put on the entrance? Please forgive my ignorance.
Registered Member #1875
Joined: Sun Dec 21 2008, 06:36PM
Location:
Posts: 635
Remember that the peak of the AC has to be half the capacitor's rating. So assuming 1.6kV is your capacitor's maximum working voltage, your maximum input would have to be under (1600/2)/(1.41) = 567V.
If the 1.6kV rating is an AC rating, then that changes things...
Registered Member #543
Joined: Tue Feb 20 2007, 04:26PM
Location: UK
Posts: 4992
Patric wrote ...
I have 6 diodes 12 kVolt and 6 capacitors 1.6 kV. I assume I can make a cockroft walton 6 X multiplier, but what is the maximum ac I can put on the entrance? Please forgive my ignorance.
The capacitors must be rated at a minimum of twice the peak . So with your caps, you can have a peak input voltage of 800V or about 570V RMS.
Registered Member #2727
Joined: Tue Mar 09 2010, 02:39PM
Location: Montevideo - Uruguay
Posts: 33
The diode 1n4007 can stand 1kV, and you need the same voltage in the diodes than the voltage you have for the capacitors . You need two in series of these diodes for synthetize each diode in your multiplier. Cheers!
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cockroft walton multiplier question
