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Disposable camera transformer driver.

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Michalis.Biochem

Sat Dec 04 2010, 08:25PM

Registered Member #3340 Joined: Wed Oct 20 2010, 07:28PM
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Posts: 69

I heard that a disposable camera transformer can be driven using the components found inside a disposable camera(i know, this is what the camera flash board circuit is doing).
but i don't know which components are crucial for this. Dr.2N3055 made a mini tesla coil using this driver, but i can't find anymore info about it.

So here is the thread about the tesla coil that was made using disposable camera parts.

So how can the driver be made?

Myke

Sat Dec 04 2010, 09:28PM

Registered Member #540 Joined: Mon Feb 19 2007, 07:49PM
Location: MIT
Posts: 969

All you really need is the resistor and transistor to drive the transformer (for the simpler boards). If it's not a simple board, it would be best to keep all the circuitry on the board and remove anything that doesn't drive the transformer. Those things would be the large capacitor, trigger coil, trigger contacts, xenon tube, small capacitor to dump energy into the trigger transformer, etc.

This is a picture of the simple driver taken off the board running from 1.5V (neon light and its current limiting resistor aren't needed for operation):

ubuntupokemoninc

Sat Dec 04 2010, 09:55PM

Banned on 1/22/2011 for repeated rule violations after multiple warnings.
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i don't see the schematic for the driver to get the 660 volts, what is it?

Michalis.Biochem

Sat Dec 04 2010, 09:57PM

Registered Member #3340 Joined: Wed Oct 20 2010, 07:28PM
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I see, and by saying simple boards you mean the boards that have only one diode, some resistors, a transformer, 2 caps and a transistor?
because that's the simplest board in terms of components i have in my possession.

ubuntupokemoninc wrote ...

i don't see the schematic for the driver to get the 660 volts, what is it?

Couldn't find a schematic either.

Myke

Sat Dec 04 2010, 11:42PM

Registered Member #540 Joined: Mon Feb 19 2007, 07:49PM
Location: MIT
Posts: 969

Michalis.Biochem wrote ...

I see, and by saying simple boards you mean the boards that have only one diode, some resistors, a transformer, 2 caps and a transistor?
because that's the simplest board in terms of components i have in my possession.

Yes, that's the simple board I'm talking about.

wrote ...

ubuntupokemoninc wrote ...

i don't see the schematic for the driver to get the 660 volts, what is it?

Couldn't find a schematic either.

He uses two drivers in series fed into a 6 stage CW multiplier as far as I can tell. You don't really need the schematics for this since you can look up each block function individually.

Michalis.Biochem

Sun Dec 05 2010, 08:15AM

Registered Member #3340 Joined: Wed Oct 20 2010, 07:28PM
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Posts: 69

Myke wrote ...

Yes, that's the simple board I'm talking about.

wrote ...

ubuntupokemoninc wrote ...

i don't see the schematic for the driver to get the 660 volts, what is it?

Couldn't find a schematic either.

He uses two drivers in series fed into a 6 stage CW multiplier as far as I can tell. You don't really need the schematics for this since you can look up each block function individually.

So what i am going to do, is to simply desolder the xformer, the transistor and one of the resistors.
I forgot to mention that the xformer on this board is not of the same type as the one in the picture shown above.
Is this going to work using this xformer?

Myke

Sun Dec 05 2010, 08:37AM

Registered Member #540 Joined: Mon Feb 19 2007, 07:49PM
Location: MIT
Posts: 969

It would be helpful to see a picture of the transformer and board before you remove stuff. I only removed the inverter from the board because it would be smaller. I think the best idea would be to leave the power supply part on the board.

Michalis.Biochem

Sun Dec 05 2010, 08:43AM

Registered Member #3340 Joined: Wed Oct 20 2010, 07:28PM
Location:
Posts: 69

Myke wrote ...

It would be helpful to see a picture of the transformer and board before you remove stuff. I only removed the inverter from the board because it would be smaller. I think the best idea would be to leave the power supply part on the board.

Here is the board

Michalis.Biochem

Mon Dec 06 2010, 10:22AM

Registered Member #3340 Joined: Wed Oct 20 2010, 07:28PM
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Ok, i think i managed to reverse engineer the camera flash board. It comes out that the xformer has 5 pins and is connected with one transistor and one of the resistors. I followed the connections and found out that 2 of the transistor pins were connected with 2 of the xformer pins and the 3rd one was free, and the resistor had both of it pins connected with other 2 pins of the xformer. As a result the xformer has one of its 5 pins free and the transistor one of its 3 pins free. Did i do the whole process well? And if i did it correct which pins are the input or the output?

Myke

Mon Dec 06 2010, 10:41PM

Registered Member #540 Joined: Mon Feb 19 2007, 07:49PM
Location: MIT
Posts: 969

Ah. Yeah. It should be the simple driver then.

See which pin of the transformer is connected to the diode. This should be your output. The input should be the pin that is connected to the switch that charges the flash on the camera. The entire thing has a common ground meaning the ground for the input is the same as the ground for the output.
Just to make sure, it would probably be the best to leave the transformer, resistor, and transistor on the board and remove everything else. (less work reassembling the driver and you don't have to worry about the phasing of the feed back coil)

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