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Registered Member #1822
Joined: Fri Nov 21 2008, 08:04PM
Location:
Posts: 300
Lets assume that the input voltage is 13.8V
I was told that if I take the 5V output from a 7805 to the base of a 2N3055 and apply 13.8V to the collector then the voltage across the emiter and ground will be 5V but, the current capacity will be much higher. Is this true? Will the 2N3055 operate as low as 5V? If not than what will? How much current will be drawn from the 7805?
On the same note, how much current can be drawn from a standard 9V battery? Intermittent duty 3hr max with direct supervision.
Registered Member #543
Joined: Tue Feb 20 2007, 04:26PM
Location: UK
Posts: 4992
The LM338 variable voltage regulator is as cheap as chips, can handle 5A continuous and 7A peaks, and will go down as low as 1V2. But don't skimp on the heatsink.
I'm not sure what you mean by a "standard" 9V battery.
Registered Member #1822
Joined: Fri Nov 21 2008, 08:04PM
Location:
Posts: 300
By standard I mean average run of the mill 9V battery. An alkaline duracell or something like that.
At this point I am not looking for solutions. I just want to know if it will work. Normally I would just use multi-sim but, I lost my copy and can find another on "the bay"
Registered Member #2099
Joined: Wed Apr 29 2009, 12:22AM
Location: Los Altos, California
Posts: 1716
cduma wrote ... Lets assume that the input voltage is 13.8V I was told that if I take the 5V output from a 7805 to the base of a 2N3055 and apply 13.8V to the collector then the voltage across the emiter and ground will be 5V but, the current capacity will be much higher. Is this true?
No. Search keyword: emitter follower. [edit] Not surprisingly, wikipedia does poorly on this subject. Overloaded with small-signal formulas, and not a word about DC bias (which is key to your problem).
Will the 2N3055 operate as low as 5V? If not than what will? How much current will be drawn from the 7805?
You seem to have a good practical grasp of voltage and current, so it's time to learn the DC circuit model for NPN bipolar transistors. Easy to find on the internet, but IMHO a tutorial would be out of place in this thread or this forum.
On the same note, how much current can be drawn from a standard 9V battery? Intermittent duty 3hr max with direct supervision.
Have you started by, uh, reading the datasheet? Go to duracell.com (or equivalent for other major brands) and follow links for OEM technical data.
Registered Member #1822
Joined: Fri Nov 21 2008, 08:04PM
Location:
Posts: 300
I concur my good fellow! I couldnt make any sense out of anything on that wiki page. Thanks for the hint on DC bias. I will continue my search for knowledge there.
I cant seem to find the max current of a 9V battery on any of the sites. They contain a plethora of charts detailing voltage drop over time but, no max current anywhere!
Registered Member #2099
Joined: Wed Apr 29 2009, 12:22AM
Location: Los Altos, California
Posts: 1716
cduma wrote ...
I cant seem to find the max current of a 9V battery on any of the sites. They contain a plethora of charts detailing voltage drop over time but, no max current anywhere!
Must confess that I already knew that, but the datasheets -do- give numbers for the internal resistance.
For alkaline batteries, a load which would theoretically discharge them in less than 2 hours ( a load greater than C/2, about 1.4 A from a AA size cell or 300 mA for 9V battery ) is well off the data sheet. Total amp-hours will be a small fraction of the Ah value with normal loads.
Initially you can extrapolate from the datasheet. But if your application is intermittent loading at multiples of C, I think you'll need to make your own measurements.
Can use a quartz wall clock, powered by the battery under test, to objectively measure how long it takes for your test load to exhaust the battery. For 9V battery you'd want a voltage divider or regulator to feed the clock.
Registered Member #2161
Joined: Fri Jun 05 2009, 03:36PM
Location:
Posts: 247
9V batteries are weak little things when it comes to current, you are looking at ~<50ma reliable draw (maybe 60-70max). I believe their general capacity is around 600mA, but that is of the top of my head, someone correct me if I am wrong.
This is for the alkaline, I do not know of the current limitation using nimh 9V battery, I do suppose a larger current draw can be expected, but not much more.
Registered Member #1792
Joined: Fri Oct 31 2008, 08:12PM
Location: University of California
Posts: 527
mikeselectricstuff wrote ...
for 13.8 to 5V at 6A you really should use a switching regulator - a linear will be burning a ridiculous amount of heat.
Quite right, about 50W in fact.
Look on a site like Analog Devices to find a chip that will do the job. Or look around on digikey/mouser/etc. The datasheet or a separate app-note will show you pretty much all you need to build a regulator using the chip. Something like this is pretty good, although it's 5A not 6A.
Course it might not be as fun to use these ready-made voltage regulator chips, if you really wanted you could design one yourself.
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