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Registered Member #1911
Joined: Mon Jan 05 2009, 06:30PM
Location: Salem, Oregon, USA
Posts: 165
My father has given me a challenge of finding how much pressure would be necessary to get a certain amount of water through a certain diameter of pipe in a certain amount of time.
The numbers are .185" diameter pipe and 3 gallons of water per minute. The pipe goes up-hill about six feet, which would be a factor necessary to account for in start-up, but once the process had begun, it would be simple because of the siphon effect.
There aren't any needs to have it account for friction or back-pressure. We're looking for an idealistic condition.
I'm more looking for an algorithm or a series of them to find out the numbers myself.
Registered Member #27
Joined: Fri Feb 03 2006, 02:20AM
Location: Hyperborea
Posts: 2058
A pipe with a given diametre without any other properties of a pipe is a hole. The rest of the information you give will just increase the chance of getting irrelevant replies.
Now think about a reservoir with an ideal hose connected to the bottom, what would the speed/pressure relationship be for you to have conservation of energy?
If you can spray the water back easily up into the reservoir you can can drive a turbine on top and have free energy. If you fall way short then your energy has disappeared somewhere...
Registered Member #1911
Joined: Mon Jan 05 2009, 06:30PM
Location: Salem, Oregon, USA
Posts: 165
Speaking of irrelevant replies...
My question is "How much pressure is needed to force three gallons of water per minute through an opening that is .185" in diameter, allows for zero expansion, is greater than twelve feet long, and has a point where it must travel up six feet, and comes down another six later?"
Registered Member #27
Joined: Fri Feb 03 2006, 02:20AM
Location: Hyperborea
Posts: 2058
In the first question you asked about an ideal case where frictions are ignored, and I gave you the method to answer that. Now you add more information without stating if you want the ideal answer once more or if you want us to google the complete formula for you.
If you had asked a proper question from the start you would have had the answer you wanted in the first reply.
Registered Member #1911
Joined: Mon Jan 05 2009, 06:30PM
Location: Salem, Oregon, USA
Posts: 165
I'm sorry that i wasn't clear. From my own understanding, I was already as clear as needed, but I suppose that I was incorrect. I will see what I can do to figure out which formulas to work with.
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