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Registered Member #1525
Joined: Mon Jun 09 2008, 12:16AM
Location: America
Posts: 294
I am going to use an inverter to feed a voltage triple to charge the caps in my coilgun. Here is the circuit:
The inverter will be putting out about 115VAC at 1.4A. Obviously, the diodes will have to be able to take 115V/1.4A, and the caps need to be rated at at least 115V, but my question is this: how do you chose the capacitance of the capacitors? I cannot seem to find this information anywhere. I appreciate any help.
Registered Member #1694
Joined: Sat Sept 13 2008, 09:13AM
Location: Australia
Posts: 108
For maximum charge time, you'll want a fairly low value resistor. However during discharge it'll have a lot of current going through it. You could do the maths yourself using V = IR and P=IV Another option would be to disconnect your voltage multiplier before you fire your gun.
Registered Member #1525
Joined: Mon Jun 09 2008, 12:16AM
Location: America
Posts: 294
I think I see what you are saying. When the voltage in my bank goes to zero, the charged caps in the multiplier are going to discharge into the empty cap bank (right?)
So then the resistor just has to keep the resulting current below 30A or so (the pulse rating for the diodes).
Registered Member #540
Joined: Mon Feb 19 2007, 07:49PM
Location: MIT
Posts: 969
I think that with more loading, the voltage of the output drops but as the load impedance increases, the voltage would increase. I think in addition to the output resistor, you need a resistor on the primary side. This isn't always needed if you have a small load on the output and the caps in the multiplier are fairly small.
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Question about Voltage Tripler
