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4hv.org :: Forums :: General Science and Electronics
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question about ignitrons

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Proud Mary
Mon Dec 01 2008, 06:36AM
Proud Mary Registered Member #543 Joined: Tue Feb 20 2007, 04:26PM
Location: UK
Posts: 4992
The peak current of mercury vapour devices cited in data sheets is put there as the basis for calculation of the series resistor, without which the device would appear as a dead short during conduction, offset by the constant voltage drop of the device, which is usually about 15V. Without this series limiting resistor, the rectifier would be destroyed.

So the peak current is not the maximum the device is able to draw left to do what it wants, but the absolute maximum which it should be permitted to draw within the integration period, where one is cited.

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saturatEd
Mon Dec 01 2008, 01:29PM
saturatEd Registered Member #1810 Joined: Thu Nov 13 2008, 02:46PM
Location:
Posts: 14
Oh, well, I don't think we are talking about the same thing here, but anyway, thanks for all the input
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Proud Mary
Mon Dec 01 2008, 04:44PM
Proud Mary Registered Member #543 Joined: Tue Feb 20 2007, 04:26PM
Location: UK
Posts: 4992
There is a chapter just about mercury vapour devices including ignitrons in the Rectifiers section of Vacuum Tube Design - RCA (1940) which you can download in .pdf (49MB) free here:

Link2

and more useful material on mercury arc devices in the Rectifiers chapter of Henney, K. Electron Tubes in Industry McGraw-Hill, New York, 1952,

which you can download free in .pdf here:

Link2

I hope you find this more helpful than I seem to have been! cheesey

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