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Registered Member #528
Joined: Fri Feb 16 2007, 10:32PM
Location: Warsaw, Poland
Posts: 166
Fraggle wrote ...
length=(mass of reel)(area of x-section)/(density of Copper)
ignoring the mass of the bobbin itself.
That's a wrong equation, because you get m^5 as length unit. The proper equation would be length = (mass of reel)/[ (area of x-section)*(density of copper) ], there you get m as unit. That was a metod I've used, but I have no idea how accurate it is. With this, I calculated that my spool with 0.45kg of 0.35mm wire has 230m of wire. What safety margin can I use? 220, 210 or 200m?
Registered Member #1526
Joined: Mon Jun 09 2008, 12:56AM
Location: UK
Posts: 216
Dammit, I hate trying to do these things in my head with ascii notation :o)
Anyways, just use the uncertainties of your mass and diameter to work out the error in the usual way. I`d bet that you`ve only got two figures by the time the errors caused by the insulation and reel add up.
Registered Member #1232
Joined: Wed Jan 16 2008, 10:53PM
Location: Doon tha Toon!
Posts: 881
I would measure the DC resistance at room temperature if you can get to both ends of the wire. Then calculate an estimate of the number of metres on the drum.
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Methods for estimating secondary's wire length on spool
