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Registered Member #1225
Joined: Sat Jan 12 2008, 01:24AM
Location: Beaumont, Texas, USA
Posts: 2253
high frequency air cored resonant transformer :)basically it works like a regular transformer except exact resonance is more essential.if you want a whole explanation of how it works let me know :)
Banned on 02/27/2008 Registered Member #1326
Joined: Sun Feb 17 2008, 11:19PM
Location:
Posts: 49
Quote from the first wiki link by goldsphere:
A Tesla Coil transformer operates in a significantly different fashion than a conventional (i.e., iron core) transformer. In a conventional transformer, the windings are very tightly coupled, and voltage gain is limited to the ratio of the numbers of turns in the windings. However, the voltage gain of a disruptive Tesla Coil can be significantly greater, since it is instead proportional to the square root of the ratio of secondary and primary inductances. The coil transfers energy from one oscillating resonant circuit (the primary) to the other (the secondary) over a number of RF cycles. As the primary energy transfers to the secondary, the secondary's output voltage increases until all of the available primary energy has been transferred to the secondary (less losses). Even with significant spark gap losses, a well designed Tesla coil can transfer over 85% of the energy initially stored in the primary capacitor to the secondary circuit.
=========== Who can show me any derivation of the voltage ratio of the loosely coupled coils as mentioned in the quote above ?
I know that for a single resonance circuit, the resonance can take the voltage of a cap to almost infinity and due to resistance you can use complex phasor analysis to find the upper limit.
No idea how to tackle loosely coupled resonant system.
Registered Member #72
Joined: Thu Feb 09 2006, 08:29AM
Location: UK St. Albans
Posts: 1659
For deriving the voltage gain, you can ignore the resonance aspects, that's just a mechanism that transfers as much of the energy from primary to secondary as losses allow, and do all the sums through energy.
Given that you know that E=1/2CV^2, and that at the voltage peak all the energy is stored in the capacitance and none in the inductance, then you can work out that the voltage gain (Vsec/Vpri) is just sqrt(Cpri/Csec) (neglecting losses).
BTW, try to avoid "almost infinity" in thinking about problems. For a single resonant circuit *being supplied with power* the voltage at resonance grows until it reaches equilibrium, that is the power loss equals the power supplied. The losses will come mainly from current flowing through resistances, though dielectric and radiation losses may add their tu'pen'th. Not so complex, and not a phasor in sight. Energy again, it's a damned handy concept!
Banned on 02/27/2008 Registered Member #1326
Joined: Sun Feb 17 2008, 11:19PM
Location:
Posts: 49
Now that I have shortened my sig and written it clearrly for safety tip, I would like to thank all those who replied yet.
However, I will work on trying to do the derivation. It is the starting point. The paper is a little too difficult and I would appreciate more references ... basic ones also to climb a smooth slope to this one.
Thanks again for your help and look forward to more.
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