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Forums
4hv.org :: Forums :: Electromagnetic Projectile Accelerators
« Previous topic | Next topic »   

New Coilgun plans..need feedback

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Shaun
Tue Nov 13 2007, 03:06AM
Shaun Registered Member #690 Joined: Tue May 08 2007, 03:47AM
Location: New Jersey, USA
Posts: 616
uF, or the Farad in general is a measure of capacitance and cannot be applied to batteries. If you want to find the total energy stored in your batteries, see if you can find an Amp-Hour rating on the battery. Amp-hours*Voltage*3600 will give joules stored. For batteries your size, it will be huge.

Far example, I have a medium-size 7Ah lead-acid battery (12V). So 7*12*3600=302,400 or about 300kJ.

Also, one thing you left out is the SCR is a polar device, and its gate must be connected to a proper low-voltage power source with limiting resistor. If you were to use an SCR, it would look something like this:

1194923148 690 FT34098 Cg

EDIT: oops, remember to put a fire switch in series with the SCR gate! I didn't!
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...
Tue Nov 13 2007, 03:13AM
... Registered Member #56 Joined: Thu Feb 09 2006, 05:02AM
Location: Southern Califorina, USA
Posts: 2445
How big of a diode, and whether you need one at all, depends on how your circuit is configured. If you want, you can actually eliminate the reverse spike completely. Of course the math behind this is pretty nasty, but you can play with Barry's calculator to see what is going on with the circuit (make sure to turn on the voltage trace at the bottom).

High speed (or super, ultra, hyper, for that matter) diodes don't really help for this application, since all silicon diodes turn on at the same speed, it is just how long they take to turn back off that changes, and you could care less about that for this application.

You could, if you wanted to, calculate the uF stored in the batteries by finding the energy available (E=V*A*T, all SI units) for a 12v 18a.hr battery that is 0.8MJ, and then use the E=.5cv^2 formula, which give 5kF (ie, 5x10^9uF).

You could replace the switch between the battery and teh caps with a resistor 10-100ohms, if you want to simplify the design a bit. I would also recommend putting the batteries in series, and if you caps are rated for <25v then also split it into 2 banks of 4 parallel caps that are in series.
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Shaun
Tue Nov 13 2007, 03:21AM
Shaun Registered Member #690 Joined: Tue May 08 2007, 03:47AM
Location: New Jersey, USA
Posts: 616
Did I hook up the SCR correctly in that last pic?
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Cwazy
Tue Nov 13 2007, 03:27AM
Cwazy Registered Member #1106 Joined: Thu Nov 08 2007, 01:15AM
Location: Seattle, Washington
Posts: 25
shaun: yeah i forgot that part, but im going to do a toggle for now.then move to scr after a lil but thanks =)

...) yeah the caps are rated for 15v. so by making 2 banks of parellel that are in series, you essiciently double the voltage right? and if i do that, what happens to my uf.? does it split into 400,000? and by making a series with my caps, i would also have to make my batteries series in order to charge it?
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Shaun
Tue Nov 13 2007, 03:44AM
Shaun Registered Member #690 Joined: Tue May 08 2007, 03:47AM
Location: New Jersey, USA
Posts: 616
Actually 4 parallel strings of 2 series caps each would be 30V rated, 200,000uF. When you put two caps in series, its half the original capacitance (of just one of the caps), and double voltage.
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Cwazy
Tue Nov 13 2007, 03:48AM
Cwazy Registered Member #1106 Joined: Thu Nov 08 2007, 01:15AM
Location: Seattle, Washington
Posts: 25
ohhhh so its 2x voltage and .25x total capacitance

k so they both give me same amount of J. so why would the parellel in series be more power?
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Shaun
Tue Nov 13 2007, 03:53AM
Shaun Registered Member #690 Joined: Tue May 08 2007, 03:47AM
Location: New Jersey, USA
Posts: 616
Higher voltage through same resistance=more amps=more power
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Cwazy
Tue Nov 13 2007, 04:04AM
Cwazy Registered Member #1106 Joined: Thu Nov 08 2007, 01:15AM
Location: Seattle, Washington
Posts: 25
oh, gotttcha, i shal experiment with both when the caps arrive :)
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Wolfram
Tue Nov 13 2007, 06:51AM
Wolfram Registered Member #33 Joined: Sat Feb 04 2006, 01:31PM
Location: Norway
Posts: 971
If you charge your caps up to their full rated voltage, you will get 56% more energy stored in them.
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Cwazy
Wed Nov 14 2007, 03:30AM
Cwazy Registered Member #1106 Joined: Thu Nov 08 2007, 01:15AM
Location: Seattle, Washington
Posts: 25
ummm how does that work??
and doesnt constant charging of caps to their limit actually hurt the caps?
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