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Registered Member #58007
Joined: Thu Nov 19 2015, 04:22PM
Location:
Posts: 3
I need a help to make a incandescent flash light to blow OFF with electromagnetic radiation( A torch with incandescent lamp inside ). A compact circuit powered with 3.7 v -12 v dc is required with no noise.
The radial distance between the radiation source and the flash light should be at least ONE feet. (for more information I have attached an image). i want to damage the filament in the flash light with electromagnetic radiation.
Please give me suggestions along with the circuit diagram.
Registered Member #11591
Joined: Wed Mar 20 2013, 08:20PM
Location: UK
Posts: 556
Not going to happen. Even if you used the most powerful non-nuclear EMP device (probably an Explosively Pumped Flux Compression Generator) the energy absorbed by the bulb would be tiny, probably unnoticeable.
This *cannot be done. Purely resistive battery operated incandescent lights even survive megawatt EMPs.
Fry a switchmode modern flashlight that isn't faraday shielded? Yes, can be done, but it's incredibly difficult and creates a ton of EM noise because that's how it's done, you impose noise on the driver circuit.
*A highly focused multi-kilowatt microwave beam might be able to vaporize a bulb filament, same as a focused CO2 laser could break the glass envelope allowing the filament to burn in air. These aren't solutions any more than walking over to it and turning the switch off is.
Even though the topic could be purely educational in scope it is most likely purposed for nefarious deeds. I advise you simply find something else worth your time to pursue.
Registered Member #162
Joined: Mon Feb 13 2006, 10:25AM
Location: United Kingdom
Posts: 3141
I beg to differ,
the lamp is designed with a reflector that focuses the light from the filament at infinity, use a light sensor to trigger when the target is aligned, now the hard part ... a really powerful e.m. wave (visible, i.r. ... to melt the glass and/or filament of the lamp ok not easy but possible.
Registered Member #54278
Joined: Sat Jan 17 2015, 04:42AM
Location: Amite, La.
Posts: 367
What is the flashlight is "almost burned out" and is hit by the (focused) pulse during it's (the lamp's) filament just as the filament-current passes through the most 'destructive' or 'vulnerable' dT/di ? Where: T= current-induced filament temperature and i = filament current? ...just pickin' for an answer here, sad case A-1.
Registered Member #96
Joined: Thu Feb 09 2006, 05:37PM
Location: CI, Earth
Posts: 4062
I suppose if you could target the filament with a high enough powered focused laser it might be possible to spot heat the tungsten beyond the evaporation point. eventually...
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