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Polytropic process vs characteristic equation for a perfect gas

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IamSmooth
Wed Dec 25 2013, 06:32PM Print
IamSmooth Registered Member #190 Joined: Fri Feb 17 2006, 12:00AM
Location:
Posts: 1567
This question is for someone knowledgeable in thermodynamics.

The polytropic law states:

(1) P1V1^n = P2V2^n

The perfect gas equation states:

PV = mRT --> P1V1/T1 = P2/V2/T2

If T1 = T2 then
(2) P1V1 = P2V2

So, how can equation 1 and 2 both be true for the same gas? If the gas follows a polytropic process, where n ≠ 1, how can 2 be correct when there is no temperature change?
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Andy
Wed Dec 25 2013, 07:10PM
Andy Registered Member #4266 Joined: Fri Dec 16 2011, 03:15AM
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Posts: 874
Hi IamSmooth
Do you mean that if temperature doesn't change but pressure or volume changes that the new pressure and volume will match?
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Dr. Slack
Wed Dec 25 2013, 07:21PM
Dr. Slack Registered Member #72 Joined: Thu Feb 09 2006, 08:29AM
Location: UK St. Albans
Posts: 1659
Try wikipedia -> Link2 on polytropic processes
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IamSmooth
Wed Dec 25 2013, 08:38PM
IamSmooth Registered Member #190 Joined: Fri Feb 17 2006, 12:00AM
Location:
Posts: 1567
Dr. Slack wrote ...

Try wikipedia -> Link2 on polytropic processes

Doesn't seem to answer the question.
On page 116 of Rayner Joel's Engineering Thermodynamics, both equations are used to derive another set of equations. One equation is setting n = 1; the other is just leaving it as n. This does not make sense.
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Andy
Wed Dec 25 2013, 09:05PM
Andy Registered Member #4266 Joined: Fri Dec 16 2011, 03:15AM
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Posts: 874
One is a close system analysis the other can take input.
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Uspring
Thu Dec 26 2013, 06:30PM
Uspring Registered Member #3988 Joined: Thu Jul 07 2011, 03:25PM
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Posts: 711
IamSmooth wrote:
If the gas follows a polytropic process, where n ≠ 1, how can 2 be correct when there is no temperature change?
Processes with n ≠ 1 change the temperature.

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Dr. Slack
Thu Dec 26 2013, 09:13PM
Dr. Slack Registered Member #72 Joined: Thu Feb 09 2006, 08:29AM
Location: UK St. Albans
Posts: 1659
IamSmooth wrote ...

Dr. Slack wrote ...

Try wikipedia -> Link2 on polytropic processes

Doesn't seem to answer the question.
On page 116 of Rayner Joel's Engineering Thermodynamics, both equations are used to derive another set of equations. One equation is setting n = 1; the other is just leaving it as n. This does not make sense.

This is a classic model/system confusion. The systems behave as they behave, under the conditions pertaining at the time. Their behaviour does not follow simple equations, their behaviour can be approximately described by simple equations. If you change the conditions, the describing equations will often change. So if you compress gas adiabatically, or isothermally, you need a different value of n, because you are operating the system under different conditions.

But I understand your pain, it would be nice if all systems followed simple rules, rather than did what they did and left us trailing in their wake trying to figure out how best to describe them.
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klugesmith
Fri Dec 27 2013, 08:17PM
klugesmith Registered Member #2099 Joined: Wed Apr 29 2009, 12:22AM
Location: Los Altos, California
Posts: 1716
Dr. Slack wrote ...

This is a classic model/system confusion. The systems behave as they behave, under the conditions pertaining at the time. Their behaviour does not follow simple equations, their behaviour can be approximately described by simple equations. If you change the conditions, the describing equations will often change. So if you compress gas adiabatically, or isothermally, you need a different value of n, because you are operating the system under different conditions.

But I understand your pain, it would be nice if all systems followed simple rules, rather than did what they did and left us trailing in their wake trying to figure out how best to describe them.

Well said, and not just applicable to thermodynamics.
It brings to mind:
"All models are wrong, but some models are useful."
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klugesmith
Sat Dec 28 2013, 04:30AM
klugesmith Registered Member #2099 Joined: Wed Apr 29 2009, 12:22AM
Location: Los Altos, California
Posts: 1716
Adding words to questions already answered.
Suppose you have an ideal gas initially at P1, V1, T1 state.
And you expand it to P2 < P1.

If you do that isothermally, volume goes up in same ratio as pressure goes down. Some heat must be supplied, and some work can be done.

Suppose you expand it adiabiatically and reversibly (isentropically) instead.
Then the temperature drops. The final volume (and work done) are less than in the isothermal case.
The pressure ratio is split between temperature ratio and volume ratio, according to a polytropic exponent called gamma.
(gases following the gamma law can still be ideal).

Simply saying "adiabatic expansion" is NOT sufficient to figure the final temperature and volume.
We're still talking about ideal gas and simple equations of state.
But if the expansion is, for example, through a porous plug, no work is done,
though the final temperature and volume are greater than with reversible expansion.

Argh!
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IamSmooth
Sun Dec 29 2013, 12:50AM
IamSmooth Registered Member #190 Joined: Fri Feb 17 2006, 12:00AM
Location:
Posts: 1567
Someone answered this question to me by saying that

P1V1^n = P2V2^n does not do so isothermally. If it were isothermal it would just be P1V1 = P2V2

P1V1/T1 = P2V2/T2 is the ideal gas equation and accounts for all three variables.
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