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4hv.org :: Forums :: Tesla Coils
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Class-E Coil Modes of Operation

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dude_500
Fri Dec 06 2013, 06:27AM Print
dude_500 Registered Member #2288 Joined: Wed Aug 12 2009, 10:42PM
Location: Cambridge, MA
Posts: 179
I'm working on a 4MHz class-E coil and got it working somewhat (need to adjust the coupling as it's somewhat under-damped right now), but there seem to be two modes of operation, one correct and one incorrect.

The power stage topology is simply a FET with primary between the drain and positive rail. When everything is tuned right, I get an expected class-E waveform (VDS on top, resonant gate drive on bottom):


1386311038 2288 FT0 Img 20131205 225602


But, if I adjust the frequency by as little as 50-100khz away from 4MHz, it changes mode into the following (voltage scaling is same as the previous waveform):


1386311116 2288 FT0 Img 20131205 225611


So far, no more than 50V rail has been put on it since I fear that if it enters this undesirable mode of operation as voltage goes up, it'll blow the FET from VDS breakdown.

According to SPICE simulation, this actually is expected behavior. I'm having a hard time getting a good intuition for what is causing it, though. It seems to be an alternation between charging up the secondary tank and then having it dump back to the primary. Is there a way to avoid this mode, or make it require more frequency deviation before entering it?


1386311261 2288 FT0 Img 20131205 225554

1386311261 2288 FT0 Img 20131205 231235
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johnf
Fri Dec 06 2013, 09:29AM
johnf Registered Member #230 Joined: Tue Feb 21 2006, 08:01PM
Location: Gracefield lower Hutt
Posts: 284
you are going off tune and the output transfer is going at half freq. This is one of the problems with high order classes of amplifier drive.
I have had to rework glass G Rf amplifiers where the drive level as well as the resonance is important to maintain output at the desired level. A 1dB change in input made a 5 dB and mode change in output level.

A reduction in Q may help ie more L less C. In general tuned circuits the Q is proportional to the C value ie lower l higher c = higher Q
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