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Registered Member #162
Joined: Mon Feb 13 2006, 10:25AM
Location: United Kingdom
Posts: 3140
If you already have a suitable bobbin then ignore the rest; assuming a forward converter topology; if you are going to make the bobbin, consider winding the primary in four sections, one for each outer limb of the ferrite, then for each 1/4 primary winding have one of the secondaries, this uses less copper (resistance) and is easier to wind and to insulate. Of course you will have two round and two square sets of windings.
The auxiliary winding can be insulated wire wound directly onto one of the remaining two limbs, easy to adjust.
Registered Member #152
Joined: Sun Feb 12 2006, 03:36PM
Location: Czech Rep.
Posts: 3384
For a square wave with 50/50 duty cycle, N=V/(4*f*B*A). N=number of turns, V=applied voltage, f=frequency, B=flux density (try 0.3 up to some 30 kHz, 0.2 for 60kHz), A=core area (m^2).
Registered Member #3324
Joined: Sun Oct 17 2010, 06:57PM
Location:
Posts: 1276
Sulaiman wrote ...
If you already have a suitable bobbin then ignore the rest; assuming a forward converter topology; if you are going to make the bobbin, consider winding the primary in four sections, one for each outer limb of the ferrite, then for each 1/4 primary winding have one of the secondaries, this uses less copper (resistance) and is easier to wind and to insulate. Of course you will have two round and two square sets of windings.
The auxiliary winding can be insulated wire wound directly onto one of the remaining two limbs, easy to adjust.
Sadly, i know very little about the topologys, the only ones im really familire with is a full-bridge or half-bridge driven from a TL494 is there any good example schematics that people often use as a base for the circuit build? thanks, Thomas Williamson
Registered Member #3324
Joined: Sun Oct 17 2010, 06:57PM
Location:
Posts: 1276
I feel like a complete idiot now.... used google to convert because i was too lazy and didnt put the 2 at the end.... *facepalms* 320/ (0.0007069*60000*4*0.2) = 9.43
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