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4hv.org :: Forums :: High Voltage
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Building a voltage multiplier.

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tarakan2
Wed Apr 24 2013, 06:08PM Print
tarakan2 Registered Member #3859 Joined: Sun May 01 2011, 03:47PM
Location:
Posts: 179
Hello.
I would like to hear some practical advice before I buy parts to build a CW voltage multiplier.

  • I realized that diodes increase in price after 3KV.

  • I heared that there is a reason to place larger value capacitors at the bottom of the multiplier. Why is it a good idea?

  • What capacitors should I use?

  • It is likely that I will build my multiplier around a high frequency transformer HV power supply that tends to lose voltage when current is drawn from it. If my supply produces a peak voltage of 5KV, should I use diodes that are rated to hold 5 KV and capacitors that hold 5 KV ?

  • Is there any way I can save money by using different capacitors and diodes throughout the circuit?

  • What is the most cost-effective voltage to multiply in your opinion? (1KV, 3KV, 10KV, 100KV ?)

  • Would diodes leak at kilohertz frequency?

  • What capacitor values are the most efficient economically?


I will use this setup for Kirlian photography experiments and maybe to build an electrodynamic hoover craft. I am not sure what kind of currents this will demand.

Thank you
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HV Enthusiast
Wed Apr 24 2013, 06:47PM
HV Enthusiast Registered Member #15 Joined: Thu Feb 02 2006, 01:11PM
Location:
Posts: 3068
Do you have an idea how much output current and voltage you will require? I'm not familiar enough with Kirlian photography and the hovercraft application you mention to throw a voltage / current number out there.
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tarakan2
Wed Apr 24 2013, 07:41PM
tarakan2 Registered Member #3859 Joined: Sun May 01 2011, 03:47PM
Location:
Posts: 179
This is a good question.
I know a formula

The voltage drop under load can be calculated as:

Edrop = I1/ (f*C) * (2 /3*n^3 + n^2/2- n/6)
where:
I is the load current
C is the stage capacitance
f is the AC frequency
n is the number of stages.

The ripple voltage, in the case where all stage capacitances (C1 through C(2*n)) may be calculated from:
Eripple = Iload/(f * C)*n*(n+1)/2

But I have no idea, how much power output I want.
I assume that I need to look for a power supply first.

This means that I need to know WHAT VOLTAGE INCREMENTS I should work with.

So what voltage increments should I work with?
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HV Enthusiast
Wed Apr 24 2013, 07:57PM
HV Enthusiast Registered Member #15 Joined: Thu Feb 02 2006, 01:11PM
Location:
Posts: 3068
Two things you should think of first:

1. What is your primary voltage source which will power the CW multiplier.

2. How much voltage you need.

For example, if you're primary voltage source was a 15kV NST, then your stage voltage would be based on the input of a 15kV 60Hz source.
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tarakan2
Thu Apr 25 2013, 01:48AM
tarakan2 Registered Member #3859 Joined: Sun May 01 2011, 03:47PM
Location:
Posts: 179
I need 100KV. I am thinking of building my device in stages.
So I can add stages and acquire higher voltages if I want to.

I have a 14KHz poser supply that can crank out a peak voltage of 10000. I am pretty sure that the voltage will drop under load, but I don't know how much.

I want to go with 2KV or 20KV increments because there is a benefit to both configurations. I will more likely go with 20KV to keep things compact but 2KV will cost significantly less.

What capacitor values would I need?

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HV Enthusiast
Thu Apr 25 2013, 05:20PM
HV Enthusiast Registered Member #15 Joined: Thu Feb 02 2006, 01:11PM
Location:
Posts: 3068
Capacitor values will depend on how much output current your particular application will require.

Also, coronal discarge will become a major factor at voltages passing 15kV. You will need to carefully control all sharp points and other edges to ensure coronal discharge is reduced. All coronal discharge acts like a "load" to your multiplier and will reduce the maximum voltage the multiplier will be able to product.

Coronal discharges can be controlled by minimizing sharp points, using coronal balls over any bolts / screws, and by carefully routing all high voltage lines away from nearby grounded points and adjacent points which are at different potentials.

Hope this helps.

First thing i would do is simply deterine what your output current needs to be. From there, you can use the generic CW multiplier equations to determine what the stage capacitance is required to be.


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Dri0m
Sun Apr 28 2013, 09:12AM
Dri0m Registered Member #4497 Joined: Thu Apr 19 2012, 12:53PM
Location: Behind you
Posts: 62
kirilian photography needs AC current, but only like 2kV, which is not problem to get with AC flyback transformer, and lifter can be powered with ZVS DC flyback with 50V input... just saying
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