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Registered Member #96
Joined: Thu Feb 09 2006, 05:37PM
Location: CI, Earth
Posts: 4061
I've had some experience with these, putting a 1K resistor across the diode(s) speeds up switching transitions by discharging the device capacitance of tens of pF.
Registered Member #2431
Joined: Tue Oct 13 2009, 09:47PM
Location: Chico, CA. USA
Posts: 5639
Conundrum wrote ...
I've had some experience with these, putting a 1K resistor across the diode(s) speeds up switching transitions by discharging the device capacitance of tens of pF.
do you mean a 1K resistor across A and K ? im thinking of using a logic type IC with a series resistor, but a second resistor, means a V divider.
Registered Member #3215
Joined: Sun Sept 19 2010, 08:42PM
Location:
Posts: 780
you don't want full-on and full-off
there must still be biasing when OFF (5-10% of nominal current generally speaking) as to be placed just under the treshold, so you throw away the inertial part of the curve, and you achieve better optical pulses
the diode capacitance stays charged, but you modulate current
Registered Member #2431
Joined: Tue Oct 13 2009, 09:47PM
Location: Chico, CA. USA
Posts: 5639
Shrad wrote ...
you don't want full-on and full-off
there must still be biasing when OFF (5-10% of nominal current generally speaking) as to be placed just under the treshold, so you throw away the inertial part of the curve, and you achieve better optical pulses
the diode capacitance stays charged, but you modulate current
you are saying 'current', do you mean voltage? keeping the forward voltage drop just barely applied at the OFF condition, so the ON condition can be reached sooner?
Registered Member #509
Joined: Sat Feb 10 2007, 07:02AM
Location:
Posts: 329
Patrick wrote ...
Shrad wrote ...
you don't want full-on and full-off
there must still be biasing when OFF (5-10% of nominal current generally speaking) as to be placed just under the treshold, so you throw away the inertial part of the curve, and you achieve better optical pulses
the diode capacitance stays charged, but you modulate current
you are saying 'current', do you mean voltage? keeping the forward voltage drop just barely applied at the OFF condition, so the ON condition can be reached sooner?
Diodes (laser and plain ol light emitting) are driven as constant current devices generally when driving them progresses beyond a voltage source and resistor. The Vf varies with temperature, and from diode to diode, and the V/I curve is rather steep, so a modulated current source would be desirable.
Registered Member #2431
Joined: Tue Oct 13 2009, 09:47PM
Location: Chico, CA. USA
Posts: 5639
ConKbot of Doom wrote ...
Patrick wrote ...
Shrad wrote ...
you don't want full-on and full-off
there must still be biasing when OFF (5-10% of nominal current generally speaking) as to be placed just under the treshold, so you throw away the inertial part of the curve, and you achieve better optical pulses
the diode capacitance stays charged, but you modulate current
you are saying 'current', do you mean voltage? keeping the forward voltage drop just barely applied at the OFF condition, so the ON condition can be reached sooner?
Diodes (laser and plain ol light emitting) are driven as constant current devices generally when driving them progresses beyond a voltage source and resistor. The Vf varies with temperature, and from diode to diode, and the V/I curve is rather steep, so a modulated current source would be desirable.
Oh! Duh on my part! yes the V/I curve is what i should be looking at. i see what conk and shrad meant... so if i have the tinyest amout of current conduting at the Vf, then its nearly off.
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