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Registered Member #1451
Joined: Wed Apr 23 2008, 03:48AM
Location: Boulder, Co
Posts: 661
I would wind it into a solenoid, stick it in a liquid He bath, bury it under the sidewalk, and start with the practical jokes! I bet you could suck someones pants off by the zipper with a field that large! Too bad money in the US isn't magnetic.... No one would be able to pick up those coins of the sidewalk!
Registered Member #3888
Joined: Sun May 15 2011, 09:50PM
Location: Erie, PA
Posts: 649
You could still affect the coins inductively. shoot them out of their pockets or what not. I wonder what the effects of such a magnetic field on the human brain would be. If you had that kind of current flowing in such a small space, wouldn't the electrons start to repel each other so much that they'd launch each other off the conductor?
Registered Member #1792
Joined: Fri Oct 31 2008, 08:12PM
Location: University of California
Posts: 527
radiotech wrote ...
How would you deal with the magnetic field produced by the 100,000 Amp wire? If someone plucked it , what would cause it to stop vibrating?
Well if you're talking about vibration, i.e. oscillation, then radiation can slowly bleed away the energy. That's why the infamous two-capacitor problem still works with superconducting lossless capacitors, switches, and wires
Registered Member #2063
Joined: Sat Apr 04 2009, 03:16PM
Location: Toronto
Posts: 352
wait a second, if you're shorting out a car battery with a super-conducting wire, it should have 0 volts accross the wire and as much amps as the battery can provide.
Registered Member #1875
Joined: Sun Dec 21 2008, 06:36PM
Location:
Posts: 635
The voltage will be across the battery's internal resistance, though. But this conversation is dealing with magnetic loading, so the voltage would presumably be across the wire's inductance, rather than the resistance. V=IR in high school, but V=IZ in reality ;)
Registered Member #1792
Joined: Fri Oct 31 2008, 08:12PM
Location: University of California
Posts: 527
There would be some voltage across the inductance of the superconducting wire initially, but it will fall exponentially with time constant L/R and quickly become negligible. Plus a voltage sustained across a current carrying zero-resistance inductor does not actually result in any power dissipation, some energy is temporarily built up in the magnetic field around the inductor when voltage and current are both positive at a terminal, but this energy will eventually be released outside of the inductor where it is used or turned into heat.
Registered Member #1451
Joined: Wed Apr 23 2008, 03:48AM
Location: Boulder, Co
Posts: 661
In reality there is resistance in the superconducting wire, it's just really really low. The magnets on CERN's LHC carry 20,000A and have a voltage across them of only a few milivolts.
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