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Registered Member #2463
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Capacitors aside, half of a full wave doubler has to look to comparing RMS watts in to Average watts out. Sin wave, starting to peak its (.707 *peak /2) * I Rms watts in = (.318 * peak) * I Average watts out. As capacitors are added to reduce ripple the input current waveform changes from Sin to approach square.
So the output statement has to include the ripple.
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The "thermal converter" measures watts. If the 60 Hz current has a sin waveform, then the product of the voltage * current* cos (phase angle) will be watts, and the voltage be measured in RMS volts. As such, that instrument cannot indicate peak watts because peak watts would imply peak heat. Because it has two transformers, it cannot indicate average watts. So what is left? RMS watts.
Registered Member #2481
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radiotech wrote ...
The "thermal converter" measures watts. If the 60 Hz current has a sin waveform, then the product of the voltage * current* cos (phase angle) will be watts, and the voltage be measured in RMS volts. As such, that instrument cannot indicate peak watts because peak watts would imply peak heat. Because it has two transformers, it cannot indicate average watts. So what is left? RMS watts.
Wasn't the renowned James Watt from Scotland?
RMS watt has no physical meaning...
Power can be either instantaneous or average, but NOT rms...
Registered Member #2463
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Generators are rated in mVA because that represents the sizing of conductors needed. The power output is is in mW and is sold as that. It has been the custom for ages to run those with a power factor, however with energy so expensive these days that is being rethought,
Luca said : Power can be either instantaneous or average, but NOT rms...
If you are starting with a sin wave, as the point of this thread is, and want to know the efficiency of the converter, the wattmeter measuring the input will be calibrated in RMS volts * Amps * pf
Why the thermal wattmeter is suggested, is that it will measure the thermal equivalent, in watts of the power in.
To get at the power input easily, a thermal ammeter could be used with a RMS voltmeter. They can be had if searched for.
The fact that RMS Watts are not equivalent to Thermal Watts is correct. These things measure I^R in both halves of waveform.
The RMS voltage * current (resistive) ends up at the same level of power.
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RMS volts * RMS amps * PF is real power, measured in watts. Watts are work done per unit time, hence always an average quantity. There is really no such thing as "instantaneous" power. I guess the term is used loosely, to mean work done in a very small unit of time, in the same sense as "infinitesimal" in calculus.
Note that there are two kinds of power factor: displacement power factor, which is the regular "cos phi" kind, and harmonic power factor, which is the result of the voltage and current waveforms having different shapes, even if they are in phase.
Any decent wattmeter should take account of both power factors, and tell you the real power passing through it, in the thermodynamic "rate of work" sense.
RMS volts * RMS amps is apparent power, measured in VA.
If you take the vector difference of your apparent power and your real power, what you have left is reactive or imaginary power, which has a time average of zero, hence technically doesn't exist at all.
There is no such thing as RMS or thermal watts. Well, maybe in North America where they measure air conditioning in tons, gravity in slugs per square fortnight and so on.
Registered Member #2481
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Steve McConner wrote ...
RMS volts * RMS amps * PF is real power, measured in watts. Watts are work done per unit time, hence always an average quantity. There is really no such thing as "instantaneous" power. I guess the term is used loosely, to mean work done in a very small unit of time, in the same sense as "infinitesimal" in calculus.
Istantaneous power = limit Dt-->0 DW/Dt where W is work and t is time...
However, I agree that the most meaningful way to represent power is the "average" value, but definitely not the rms value.
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If you take the vector difference of your apparent power and your real power, what you have left is reactive or imaginary power, which has a time average of zero, hence technically doesn't exist at all.
The truck and trade of a power dispatcher in pre-computer days was to move megawatts and megavars (mW and mVA) around the system. It was common to think of reactive power as a quantity moving from one place to another when the controls for both the generation and the load side of machinery were in one place. Once the power factor had been decided and set on a machine,the next question was , in or out.
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