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Registered Member #61373
Joined: Sat Dec 17 2016, 01:45PM
Location: San Antonio, TX
Posts: 87
Hypothetical Problem: Assuming that both supply's have a limited current output. They would both easily push 1 amp of current through the body. Lets assume the current flowing through the body takes the same path and has the same duration. The amperage of both outputs are the same, but the 1MV supply has 1MW of energy, vs 7,200W. Does the wattage make any difference in the shock also?
What are the differences between the effects if you came onto contact with one vs the other? Assume you come into contact with the outputs before the devices are turned on (to eliminate arc burn effects).
Lets say a Pole Pig supplies the 7,200V and this supplies the 1MV
Registered Member #11591
Joined: Wed Mar 20 2013, 08:20PM
Location: UK
Posts: 556
A supply can either be current or voltage limited, or one, then the other, like an LED driver. It cannot be both current and voltage limited at the same time. So either it is a 1 A current limited, high voltage supply (the initial high voltage required to cause dielectric breakdown), then the voltage will be likely in the high hundreds to thousands of volts at one amp, assuming arcing occurs, and the bodies' surface resistance is broken down.
A pole pig can supply far higher currents under what would be essentially fault conditions, resulting in higher voltages and much higher destructive power.
It has to be said that a person would almost certainly die in either case though.
In the link provided, the 1 MV was used to break down the air, the voltage across that arc will be significantly less.
Registered Member #96
Joined: Thu Feb 09 2006, 05:37PM
Location: CI, Earth
Posts: 4059
Either will kill or seriously injure, what is important is low frequency. High frequency generally cooks tissue(s) so touching a HV anything is a very VERY bad idea because that streamer or others nearby could contact a live mains point incredibly easily. Google "Henry Transtrom"
Registered Member #60240
Joined: Mon May 16 2016, 07:01PM
Location:
Posts: 304
The important fact is the resistance R of your body. As hen918 already explained if you have a constant voltage source U your current I through the body is U/R. If this current is higher than 100mA you may not survive.The energy/Time is UxU/R [Watt]. now you can calculate this for U = 7000 V and then for U = 1 000 000 V.
If you have a constant current source 1A is ten times the deadly limit. In this case you have IxIxR [Watt].
Registered Member #57401
Joined: Sat Sept 19 2015, 08:06PM
Location: Huntsville, AL
Posts: 10
KrowBar Posted: Tue Feb 21 2017, 11:08AM Looking at this and your other related post I think you have somehow misunderstood the way electricity works. You are over-constraining the problem in your description. Let me use an analogy. I have a 1 HP winch and a 100 HP winch - assume that both have a limited speed so either one can easily lift me at 1 foot per second - let's assume both use the same cable and both connect to me at the same point. So the lifting speed is the same for both cases, but one is putting out 1 HP and the other is putting out 100 HP, so will it feel any different?
Obviously, getting lifted at 1 foot per second will feel the same - either winch is really only "putting out" 0.364 HP to lift my 200 lbs at 1 foot/s. The key unstated parameter which resulted in overspecification was my weight, just as for your case it is the body's resistance. The actual power dissipated by the body in either case will be I^2*R even if the supply is capable of a higher voltage. It will not magically use it's full capability just as the 100 HP winch won't magically do more work lifting a fixed weight at a fixed speed. The power draw is a function of the load. My winch will only experience as much torque as I supply with my weight, just like your current limited supply will only experience as much voltage difference as you supply with the body's resistance. I'm guessing you are just getting confused because you are more used to dealing with constant voltage supplies (Coupled with the fact that truly constant current and constant voltage supplies are both only theoretical concepts - neither exists in reality)
Registered Member #61373
Joined: Sat Dec 17 2016, 01:45PM
Location: San Antonio, TX
Posts: 87
KrowBar wrote ...
KrowBar Posted: Tue Feb 21 2017, 11:08AM Looking at this and your other related post I think you have somehow misunderstood the way electricity works. You are over-constraining the problem in your description. Let me use an analogy. I have a 1 HP winch and a 100 HP winch - assume that both have a limited speed so either one can easily lift me at 1 foot per second - let's assume both use the same cable and both connect to me at the same point. So the lifting speed is the same for both cases, but one is putting out 1 HP and the other is putting out 100 HP, so will it feel any different?
Obviously, getting lifted at 1 foot per second will feel the same - either winch is really only "putting out" 0.364 HP to lift my 200 lbs at 1 foot/s. The key unstated parameter which resulted in overspecification was my weight, just as for your case it is the body's resistance. The actual power dissipated by the body in either case will be I^2*R even if the supply is capable of a higher voltage. It will not magically use it's full capability just as the 100 HP winch won't magically do more work lifting a fixed weight at a fixed speed. The power draw is a function of the load. My winch will only experience as much torque as I supply with my weight, just like your current limited supply will only experience as much voltage difference as you supply with the body's resistance. I'm guessing you are just getting confused because you are more used to dealing with constant voltage supplies (Coupled with the fact that truly constant current and constant voltage supplies are both only theoretical concepts - neither exists in reality)
That makes it a lot clearer. So the excess voltage/power will just "cruise" through you at 1MV after the body absorbs set amount of energy? Due to the body's resistance, the energy dissipation at set amps will be the same, regardless?
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