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Banned on 1/22/2011 for repeated rule violations after multiple warnings. Registered Member #3299
Joined: Sat Oct 09 2010, 08:11PM
Location: Bantown, USA
Posts: 220
My lust for more powerful arcs is kicken in, and modded a mot for roughly 15volts to power my zvs driver because i need more power!
I've never made a psu before not sure were to turn, I know I need 2 caps and a resister, but what I'm really asking what values should I use?
Registered Member #3283
Joined: Wed Oct 06 2010, 11:03PM
Location: Toronto, Canada
Posts: 29
If you're trying to build a DC power supply, you would first need to rectifiy the AC coming from the rewound MOT; a 25A-35A bridge rectifier is probably good. A large value capacitor (4700-1000uf) is probably sufficient for filtering, screw terminal type capacitors are usually the best for this. Also, remember that the RMS voltage will be higher than the AC voltage coming off the transformer. AC volts x 1.414 = DC rectified voltage.
If your output voltage is too high, you can either unwind a few turns off the MOT or you can use a couple rectifier diodes in series to drop the voltage...
Banned on 1/22/2011 for repeated rule violations after multiple warnings. Registered Member #3299
Joined: Sat Oct 09 2010, 08:11PM
Location: Bantown, USA
Posts: 220
so then do i need 2 caps to follow this circuit, and what about the resister value?
Registered Member #3283
Joined: Wed Oct 06 2010, 11:03PM
Location: Toronto, Canada
Posts: 29
An RC filter circuit like the one you posted isn't recommended for high current applications; the resistor would need to dissipate a large amount of power.
The "better" alternative is an LC filter; you basically replace the resistor with a choke. You can also "stack" several LC circuits for additional filtering if you wanted...
Banned on 1/22/2011 for repeated rule violations after multiple warnings. Registered Member #3299
Joined: Sat Oct 09 2010, 08:11PM
Location: Bantown, USA
Posts: 220
how big of a choke? Any one know were to find electrical calculations so i don't have to keep asking noobie questons?
Registered Member #3283
Joined: Wed Oct 06 2010, 11:03PM
Location: Toronto, Canada
Posts: 29
Try reading this:
In an nutshell, X = 2(pi)(F)(L) will give you an equivalent resistor that you would use in the RC equivalent of the LC circuit. In your case, F = 60Hz and X = whatever resistor you where gonna use in the RC circuit.
Banned on 1/22/2011 for repeated rule violations after multiple warnings. Registered Member #3299
Joined: Sat Oct 09 2010, 08:11PM
Location: Bantown, USA
Posts: 220
ok then 376.8 hernes should give me roughly 10 amps with 20.3 volts in right?
btw I have been taking notes on the calculations you give me.
Registered Member #3283
Joined: Wed Oct 06 2010, 11:03PM
Location: Toronto, Canada
Posts: 29
Current is not involved, I think you may be confusing the units... L = Inductance, F = frequency, X = ohms. The only time current comes into play is when you wind the choke; you simply need to make sure that the wire/windings can handle the current you need to draw...
X = 2(pi)(F)(L) involves the resistance you originally wanted to use in the RC circuit (X) and 2(pi)(F) which works out to 120(Pi). L (the inductance of the choke in henries) = x/(120 x Pi).
For example, if you wanted to use a 1k resistor in the original RC circuit: 1000/(120 x Pi) = 2.65H ... That means that you would simply sub in a 2.65H choke in the place of the 1k resistor.
If you do not have a particular resistor value in mind, you can just build a choke with a 50-100 turns of 20-16awg wire around a large ferrite core.
Banned on 1/22/2011 for repeated rule violations after multiple warnings. Registered Member #3299
Joined: Sat Oct 09 2010, 08:11PM
Location: Bantown, USA
Posts: 220
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