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Registered Member #152
Joined: Sun Feb 12 2006, 03:36PM
Location: Czech Rep.
Posts: 3384
The more you increase frequency the more drive power you need for the same voltage output, because the capacitive current from secondary top to the surroundings increase and spark "thickness" and temperature increases.
So if you wanted to design a coil with say 1MHz frequency and 1MV output, you might as well end up with megawatts of input power. On the other hand, 1MV at 50/60Hz produces just a bit of corona.
So I would say that theoretically everything is possible, practically not, because with increasing frequency you need to drop the voltage for the same power.
Registered Member #30
Joined: Fri Feb 03 2006, 10:52AM
Location: Glasgow, Scotland
Posts: 6706
I guess that's correct, but you should also be aware that L is related to the frequency.
If we say that C is roughly constant because stray capacitance places a lower bound on it, then:
f = 1/(2*pi*sqrt(LC))
hence for C constant, f is proportional to 1/(2*pi*sqrt(L))
square both sides: f^2 is proportional to 1/(4*pi^2*L)
dex's proposed equation:
V^2 = 4*pi*P*L*f = (1/f)*4*pi*P*L*f^2
substituting:
V^2 is proportional to (1/f)(4*pi*P*L)/(4*pi^2*L)
cancelling out stuff: V^2 is proportional to P/(pi*F)
since it's proportional, we can just toss out the factor of pi too
V^2 is proportional to P/F
So (assuming dex's original equation was true :) ) the higher the frequency you want, the more power you will need to produce a given voltage. If you want twice the frequency, you need twice the power.
I used this PSpice simulation set: to simulate DRSSTCs, along with the old FANTC simulator to work out the coupling and resonant modes.
Registered Member #2566
Joined: Wed Dec 23 2009, 05:52PM
Location:
Posts: 147
L in the equation is a "low frequency inductance" . Sometimes it is called DC inductance of secondary.It can be easily measured or calculated.This value of L is quite a good represantative of a 1/4 wave resonant coil terminated with big toroid.OTOH,corresponding self capacity (C) is problem to measure or calculate.It differs much more from low frequency C value in the equivalent equation.That's reason why is L more convenient parameter to use.
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Relating frequency and voltage
