 Introduction and # questions
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Chris Russell
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... not Russel!
Registered Member #1
Joined: Thu Jan 26 2006, 12:18AM
Location: Tempe, Arizona
Posts: 1052
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Nick wrote ...
One site I found said freshly fallen snow density is 160 kg/cu.m.
So Q = mL. Latent heat of fusion for water (L) is 334 kJ/kg. So Q (in kJ) is 53440. Now:
1W = 1J/s so s = J / W , s = 53440 / 600 = 89 seconds. Which seems awfully fast.
For compacted snow --> density is 481 kg/ cu.meter
Nice! I think you just missed a conversion. If Q in kJ is 53440, Q in J is 53440000. So 53440000/600 = 89000 seconds, or a bit more than a day.
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Bjørn
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Registered Member #27
Joined: Fri Feb 03 2006, 02:20AM
Location: Hyperborea
Posts: 2058
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So if my driveway is 40 m x 4 m and there is a 20 cm snowfall during the night I get 40 * 4 * 0.2 = 32 m^3 of snow. Which would take a month to melt.
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