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DRSSTC-2 Design Review (Updated Specs 8/28/09)

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Wirenut
Tue Sept 01 2009, 04:14AM
Wirenut Registered Member #141 Joined: Sat Feb 11 2006, 01:14PM
Location: Southern California
Posts: 96
From Steve Ward:

Keep the large filtering capacitors electrically close to the bridge as well. The large electrolytic capacitors serve as an energy resivior supplying hundreds of amps on demand. Too much inductance or resistance in this path will hinder performance. Having the main filter capacitors close to the bridge also reduces the burden on the decoupling capacitors. I typically size these filter capacitors such that they store maybe 20 to 50X the intended "bang" energy. The bang energy is simply given by (input power)/(bangs per second). For example, my DRSSTC-1 uses 880J of storage and runs about a 12J bang (it can really support much more!). Really, I could have used as little as 375J and have done ok (this has been tested) but these capacitors were on hand.

*Edit:
Nevermind, I just realized that this does not answer your question.

*Edit:
Maybe this can help:
Link2
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Steve Conner
Tue Sept 01 2009, 09:15AM
Steve Conner Registered Member #30 Joined: Fri Feb 03 2006, 10:52AM
Location: Glasgow, Scotland
Posts: 6706
You can't find an on-resistance figure because IGBTs don't have on-resistance.

That's not to say that they're superconducting, though. They're non-linear, so the V-I characteristic isn't a straight line and hence Ohm's Law doesn't apply. You can find a little chart of the characteristic in the datasheet. However, most DRSSTC builders seem to overdrive them right off the chart.

The current in the tank circuit is only limited by the resistance, but in any efficient coil, the resistance is so small it can be ignored. So how come the current isn't infinite? The answer is streamer loading: the sparks consume the power and stop the current from building up too high. If anything goes wrong, the tank current can indeed tend to infinity, and this is what the current limiting circuit is for!

Anyway, this means that you can't use the tank circuit resistance to calculate the primary current. Here's what you do: Pull a primary current figure out of a hat. You chose 1200 amps. Calculate the reactive voltage across your tank cap for this current. Then set your current limiter to 1200 amps and it will also protect your tank cap from overvoltage. Finally fiddle with your primary tap until you actually get 1200 amps.
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Angstrom
Tue Sept 01 2009, 12:26PM
Angstrom Registered Member #1900 Joined: Fri Jan 02 2009, 06:44PM
Location: Texas
Posts: 29
That's pretty interesting Steve, thanks for that. So I guess actually calculating the current through the system is mostly futile, and just goes by whatever you set the limiting (as you say). BUT, if for some reason you design the system for too low a limit current and its constantly tripping (probably not a good thing), how would you actually lower the primary current to prevent this? Maybe detune the primary like you say? I guess you could also lower the duty cycle and input voltage.

Maybe i'm thinking about it too much, but I don't like unknowns :P
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Steve Conner
Tue Sept 01 2009, 12:59PM
Steve Conner Registered Member #30 Joined: Fri Feb 03 2006, 10:52AM
Location: Glasgow, Scotland
Posts: 6706
Well then you have a problem, because the way that streamers load the coil is just that, unknown. And it's the streamer loading that determines the primary current.

Going by my own experience, and that of other DRSSTC builders I've corresponded with, the following rules of thumb seem to work out OK:

1. Build your secondary with the lowest resonant frequency that's practical (ie the finest wire gauge you can handle) and make it good and stubby for increased coupling. Toroid size should follow the guidelines given for spark-gap coils, if you want it to break out without a breakout point. Zo should be about 50k ohms.

2. Choose the current limit according to the size of coil, size of sparks you want, what size of IGBTs you can get and how hard you dare to overdrive them, etc. You can work back from the spark length you want, through Freau's spark length equation to get power, then divide by 120 to get bang energy, then calculate the required peak current from that assuming a 150 microsecond burst. (Longer bursts than this don't really help, nor do higher break rates, so you should use the 150 and 120 figures irrespective of what burst length and break rate you're actually going to run.)

3. Design the primary circuit to have the same resonant frequency as the secondary, and about 10 times the inverter's DC bus voltage dropped across the capacitor when a current equal to the current limit is flowing. From these two constraints you can calculate both L and C. Use the highest coupling possible without flashovers.

4. Put it all together. Adjust the primary tapping point until it works properly.

Note this is the "classic" method, it may even be in the HVWiki. Ward has some newer ideas which I think could work out better.
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Angstrom
Tue Sept 01 2009, 02:49PM
Angstrom Registered Member #1900 Joined: Fri Jan 02 2009, 06:44PM
Location: Texas
Posts: 29
That all looks good... but regarding point 3: I was told that streamers (when active) lower the resonant frequency of the secondary... and to design the primary up to 20% lower frequency than the secondary.
Of course that may not happen... but I guess you should design in that much "leeway" for tuning purposes.

I read the HVWiki through a while ago but some things were a bit vague, thanks for clarifying.
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Mads Barnkob
Tue Sept 01 2009, 04:30PM
Mads Barnkob Registered Member #1403 Joined: Tue Mar 18 2008, 06:05PM
Location: Denmark, Odense C
Posts: 1968
Angstrom is right, the HVWiki article on the DRSSTC could really use a update with some of the information in this thread :)

I am keeping an eye on this thread, its all good so far!

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Austin
Fri Sept 04 2009, 09:47PM
Austin Registered Member #1169 Joined: Wed Dec 12 2007, 09:16AM
Location: Portland OR
Posts: 251
Steve McConner wrote ...

Well then you have a problem, because the way that streamers load the coil is just that, unknown. And it's the streamer loading that determines the primary current.

Going by my own experience, and that of other DRSSTC builders I've corresponded with, the following rules of thumb seem to work out OK:

1. Build your secondary with the lowest resonant frequency that's practical (ie the finest wire gauge you can handle) and make it good and stubby for increased coupling. Toroid size should follow the guidelines given for spark-gap coils, if you want it to break out without a breakout point. Zo should be about 50k ohms.

2. Choose the current limit according to the size of coil, size of sparks you want, what size of IGBTs you can get and how hard you dare to overdrive them, etc. You can work back from the spark length you want, through Freau's spark length equation to get power, then divide by 120 to get bang energy, then calculate the required peak current from that assuming a 150 microsecond burst. (Longer bursts than this don't really help, nor do higher break rates, so you should use the 150 and 120 figures irrespective of what burst length and break rate you're actually going to run.)

3. Design the primary circuit to have the same resonant frequency as the secondary, and about 10 times the inverter's DC bus voltage dropped across the capacitor when a current equal to the current limit is flowing. From these two constraints you can calculate both L and C. Use the highest coupling possible without flashovers.

4. Put it all together. Adjust the primary tapping point until it works properly.

Note this is the "classic" method, it may even be in the HVWiki. Ward has some newer ideas which I think could work out better.

so the peak current through the primary is determined by the streamer loading correct? lets say i want a 12.5' streamer...

Power in = 240volts x 30amp = 7200watts <-- I am assuming power in for DRSSTC is still the wall power
spark length = 1.77 x sqrt(Pin) = 12.5'

60hz = 120BPS

Bang energy = 7200watts / 120BPS = 60 Joules <-- required Bang Energy for 12.5 foot streamers

Bang energy of cap = Ec

Vp = SQRT( 2xEc / C )

Vp = Peak voltage seen @ MMC with a 12.5' streamer load correct?
Vp = 10954.45 @ 1uf
Vp = 12649.11 @ .75uf <--- Trying out different MMC sizes (voltage peak increases as cap size goes down)
Vp = 14142.13 @ .6uf

R = Capacitance reactance of MMC correct? (calculated from online calculator)
R = 3.979 @ 1uf
R = 5.305 @ .75uf <-- Resistance goes down as Capacitance goes up
R = 6.631 @ .6uf

Ip = Peak Current = Vp / R
Ip = 2752 amps @1uf
Ip = 2384 amps @.75uf <-- Peak Current goes down as cap size goes down
Ip = 2132 amps @.6uf

so if I choose a .6uf MMC size it will see a peak voltage of about 14142.3 volts and peak current of 2132amps
I am assuming the max amount of amps I can pump through the primary is limited by how much my IGBTs can take?

Also I want to design my filter caps with about 20x my original Bang Energy?
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Steve Conner
Sat Sept 05 2009, 09:42AM
Steve Conner Registered Member #30 Joined: Fri Feb 03 2006, 10:52AM
Location: Glasgow, Scotland
Posts: 6706
Well, that's not necessarily true. The whole point of the DRSSTC is that the bang energy can be greater than the amount of energy the tank capacitor can store. Most of the energy comes straight from your filter caps, and the tank cap is mostly just there as an impedance matching device.

That's why I suggest using the "10x your DC bus voltage" rule of thumb to size the capacitor, instead of the energy equation.

In this case your effective DC bus voltage is 677/2 because you have a half bridge, so you design your tank cap to take about 4kV.

Now if we pick a 2500 amp current limit, which is reasonable for CM600s, the tank capacitance is calculated by finding the reactance that drops 4kV at 2500 amps and 40kHz.

You then do a sanity check to make sure that the above setup can deliver 60 joules in 150 microseconds. Well, you can get away with 300us.

So the power delivered is roughly (677/2)*(4/pi)*2500, then divide by 2 to convert from peak to RMS, and another 2 to account for the ringup. The 4/pi is a conversion factor needed because the voltage is a square wave but the current is a sine wave.

Anyway that gives us about 270 kilowatts, which is 27 joules of bang energy per 100 microseconds of burst length. So in 300us, you'll deliver about 54J. Probably more, as the ringup will be complete before 300us.

This is just a rough calculation with a lot of assumptions made, but it shows you're in the ballpark.

PS: I managed to get a hold of Steve Ward, and he said he "didn't strongly disagree" with anything I said in this thread. Still, your mileage may vary tongue
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Austin
Mon Sept 07 2009, 02:31AM
Austin Registered Member #1169 Joined: Wed Dec 12 2007, 09:16AM
Location: Portland OR
Posts: 251
wrote ...

That's why I suggest using the "10x your DC bus voltage" rule of thumb to size the capacitor, instead of the energy equation.
So just to clarify... the capacitance reactance is not a good way to determine the peak voltage drop across the MMC tank. The reason for this is because at resonance the impedance from the L and C cancel each other out? instead pk voltage is coming from the Filter caps.

wrote ...
In this case your effective DC bus voltage is 677/2 because you have a half bridge, so you design your tank cap to take about 4kV.
if I had a full bridge (which I will most likely do) the peak voltage rating of my MMC should be 6770VDC.

wrote ...
Now if we pick a 2500 amp current limit, which is reasonable for CM600s, the tank capacitance is calculated by finding the reactance that drops 4kV at 2500 amps and 40kHz.

Using R = V/I = 4000/2500
R = 1.60 ohms?

And using XC = 1 / (2 * pi * f * C), where f=40khz and C=2.5uf
XC = 1.592 ohms?

2.5uf seems too big...

wrote ...
You then do a sanity check to make sure that the above setup can deliver 60 joules in 150 microseconds. Well, you can get away with 300us.

So the power delivered is roughly (677/2)*(4/pi)*2500, then divide by 2 to convert from peak to RMS, and another 2 to account for the ringup. The 4/pi is a conversion factor needed because the voltage is a square wave but the current is a sine wave.

Anyway that gives us about 270 kilowatts, which is 27 joules of bang energy per 100 microseconds of burst length. So in 300us, you'll deliver about 54J. Probably more, as the ringup will be complete before 300us.

This is just a rough calculation with a lot of assumptions made, but it shows you're in the ballpark.

PS: I managed to get a hold of Steve Ward, and he said he "didn't strongly disagree" with anything I said in this thread. Still, your mileage may vary tongue

Going back to the previous Spark Length equation.... The Input power (Pi) is the power from the wall? Or from the Inverter Or from the primary MMC / Inductor. I just assumed 240volts RMS X 30amps = 7200 watts because that is how they would do it for a spark gap coil, but I have a feeling this is wrong.

I do appreciate your help on this Steve. I sent a couple of PMs to our vents here (who I could consider vets anyways). There seems to be quite a bit of confusion when designing MMCs.

From my E-mails with Steve Ward, it sounded like he was comfortable with the idea of setting the voltage peak of the MMC based on the capacitance reactance and current limit.
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Angstrom
Tue Sept 08 2009, 04:21AM
Angstrom Registered Member #1900 Joined: Fri Jan 02 2009, 06:44PM
Location: Texas
Posts: 29
I think that both methods work here. The way I see it, Steve's method is more efficient for getting a good MMC size (big enough, but not oversized). Whereas calculating the voltage rating from capacitance/fo would prevent an issue arising from error in estimating the MMC rating to be 10x the bus voltage.

I'm not entirely convinced that 10x is enough... given that the coils I worked with this weekend had an MMC rating of 12kV (with a voltage doubled 208V bus = 400V).

Of course, like he says, these are unpredictable creatures. I recommend you don't worry about it TOO much more... and just get building.
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