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4hv.org :: Forums :: High Voltage
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Marx vs. WC multiplier

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IamSmooth
Wed Mar 08 2006, 08:51PM
IamSmooth Registered Member #190 Joined: Fri Feb 17 2006, 12:00AM
Location:
Posts: 1567
Would a NST of 15kv/60ma be sufficient or do we need much higher current?
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HV Enthusiast
Wed Mar 08 2006, 09:02PM
HV Enthusiast Registered Member #15 Joined: Thu Feb 02 2006, 01:11PM
Location:
Posts: 3068
IamSmooth wrote ...

Would a NST of 15kv/60ma be sufficient or do we need much higher current?

Yes, but remember with a standard CW multiplier, you can only use one leg of the 15kV/60mA NST since it is center-tapped grounded.

There are other CW configurations, but they require additional diodes, capacitors, etc... to be able to work from a center-tap grounded NST.
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vasil
Wed Mar 08 2006, 09:23PM
vasil Registered Member #229 Joined: Tue Feb 21 2006, 07:33PM
Location: Romania
Posts: 506
Why only a leg?
I have to ask, before making some stupid...

vasil
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HV Enthusiast
Wed Mar 08 2006, 11:09PM
HV Enthusiast Registered Member #15 Joined: Thu Feb 02 2006, 01:11PM
Location:
Posts: 3068
The RTN of the CW multiplier should be ground. On an NST, the center-tap is tied hard to the case and is usually grounded to earth ground.

For the standard CW multiplier, you only use 1/2 of the NST unless of course you have a truly floating secondary on the NST which is typically quite rare in 12kV and 15kV units.
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teravolt
Thu Mar 09 2006, 04:52AM
teravolt Registered Member #195 Joined: Fri Feb 17 2006, 08:27PM
Location: Berkeley, ca.
Posts: 1111
you could use an ignition coil to charge a marx if it was reprated to about 1kHz and rectified. There are versions of CW that use a center tap. Also you could use a + and - CW to charge each side of your capasitors. With a NST you could use each terminal to generate your + and -. Remember that each terminal is capible of generating (.5*V-secondary)*1.141=Vp, a single terminal peak output. Each diode and capasitor of a CW is one section so multiplying Vp*each section=Vo. Polarity of each CW just depends on the direction of the diodes.
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Self Defenestrate
Thu Mar 09 2006, 05:04AM
Self Defenestrate Registered Member #87 Joined: Thu Feb 09 2006, 01:36PM
Location: San Jose
Posts: 191
You could make a full wave CW, and then use of the midpoint ground.
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Dr. Shark
Thu Mar 09 2006, 08:51AM
Dr. Shark Registered Member #75 Joined: Thu Feb 09 2006, 09:30AM
Location: Montana, USA
Posts: 711
Now thats another big advantage for the Marx generator: You can use any iron-core HV transformer, rectify it up, and you are ready to go. With a CW you need to use as high a frequency as your diodes can stand, at least 10kHz (so you better get fast diodes), because the opertating frequency basically sets the output current. DONT operate a CW off a NST, unless you have a bunch of spare 10uF energy discharge caps you plan to use in place of the usual 10nF caps .-)
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HV Enthusiast
Thu Mar 09 2006, 12:47PM
HV Enthusiast Registered Member #15 Joined: Thu Feb 02 2006, 01:11PM
Location:
Posts: 3068
teravolt wrote ...

With a NST you could use each terminal to generate your + and -. Remember that each terminal is capible of generating (.5*V-secondary)*1.141=Vp, a single terminal peak output. Each diode and capasitor of a CW is one section so multiplying Vp*each section=Vo. Polarity of each CW just depends on the direction of the diodes.

You could, but even though you are charging the marx generators capacitors in this floating NST powered CW configuration, the charge voltage seen at that marx generator's capacitors to ground would still only be 1/2 the voltage.

Dan
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vasil
Thu Mar 09 2006, 01:41PM
vasil Registered Member #229 Joined: Tue Feb 21 2006, 07:33PM
Location: Romania
Posts: 506
I see.
I will try to use an insulation transformer (secondary middle floating).
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