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4hv.org :: Forums :: General Chatting
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Dimming lights.

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Platinum
Fri Mar 15 2013, 05:08PM
Platinum Registered Member #3926 Joined: Fri Jun 03 2011, 08:32PM
Location: UK.
Posts: 525
It will happen whenever you turn an high power appliance on, for my house anything over 700watt and voltage drops and my lights sag. When I turn my kettle (1KW~)on the light dim slightly. If I turn my welder on, ohh wait I can't. My arc welder pulls huge amounts of power even in open circuit it trips my breaker. Lol.
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StormInABottle
Fri Mar 15 2013, 06:20PM
StormInABottle Registered Member #9252 Joined: Fri Jan 04 2013, 06:27AM
Location: Andromeda
Posts: 253
Hehe. That never happens tho unless i draw some 7000 watts. IF you wish to know i stacked 14 500 watt light bulbs as a ballast to keep shorting the mains. Soo much lovely explosions. And i can also weld .. Well a little bit with it :D. Just take a piece of solder and hook it to a wire. And you have a soldering iron :D. but it happens a slight bit when using my mot stack. but it is alot more noticeable with that 7000 watt thing Btw. my kettle is 2500 watts and my hair dryer is 3000 XD. But when i tried to measure the washing machine my meter popped :D
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Uspring
Sat Mar 16 2013, 01:15PM
Uspring Registered Member #3988 Joined: Thu Jul 07 2011, 03:25PM
Location:
Posts: 711
Arcingnoob wrote:
The lights in the room become dimmer the more you stretch the arc.
I find this counterintuitive. Shorter arcs have less resistance than longer ones. When you draw the arc long, the ballast bulbs should dim, while your room lights brighten. Do you see any change in the brightness of the ballast bulbs?

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Harry
Sat Mar 16 2013, 02:16PM
Harry Registered Member #4081 Joined: Wed Aug 31 2011, 06:40PM
Location: UK
Posts: 139
Uspring it's because arcs exhibit a phenomenon known as 'negative resistance.'
Wiki link for arcs: Link2 and negative resistance: Link2
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Uspring
Sat Mar 16 2013, 07:29PM
Uspring Registered Member #3988 Joined: Thu Jul 07 2011, 03:25PM
Location:
Posts: 711
You bring up an interesting point. Imagine a V versus I diagram of a typical arc. It comes down from the top along the V axis and curves down to the right along the I axis. (I tried to draw an ASCII version of this but this usually nice user interface interfered with the formatting). The operating voltages and currents can be read of this diagram to be the intersections between the ballast curve (a straight line from the top left to the bottom right) and the curve of the arc.

You get 2 intersections, one high voltage/low current one and one low voltage/high current one. Since the arcs V-I curve moves up for increasing arc length, you'll get an increasing current for the high voltage intersection and a decreasing current for the low voltage one.

I believe an arc operates only at the low voltage intersection since this seems to be the only stable one. The reason is basically, that the total differential resistance i.e. the sum of the resistance of the ballast and the differential resistance of the arc is negative for the high voltage intersection. It is positive for the other one.

That low voltage intersection shows thus a decreasing power consumption with growing arc length. I'm not at all sure, though, which operating point the arc chooses.

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