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4hv.org :: Forums :: Electromagnetic Projectile Accelerators
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Coaxial LC design for pulse compression using a moving short

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Uspring
Fri Mar 13 2015, 10:02AM
Uspring Registered Member #3988 Joined: Thu Jul 07 2011, 03:25PM
Location:
Posts: 711
I * dL/dt = F*v/I
Yes, that's, what I suggested. It certainly doesn't hold, though, in the case of magnets moving near a coil such as in a motor. It might be true for the case of a projectile, which is not magnetized itself, i.e. only by the surrounding field.
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Uspring
Tue Mar 17 2015, 09:04AM
Uspring Registered Member #3988 Joined: Thu Jul 07 2011, 03:25PM
Location:
Posts: 711
I've found some sort of a proof for that the term I * dL/dt contains the complete backEMF. Therefore we have for the coil voltage:

V = L * dI/dt + I * dL/dt

and for the force:

F = 1/2 * dL/dx * I^2

For e.g. constant coil current 50% of the energy suppiled through backEMF goes into mechanical energy and 50% into the magnetic field energy. If L(x) is known a full simulation could be made inside spice.
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Shrad
Tue Mar 17 2015, 10:15AM
Shrad Registered Member #3215 Joined: Sun Sept 19 2010, 08:42PM
Location:
Posts: 780
thanks guys for the formulas, that makes it all clearer

in the case of a projectile being a moving short, it would be magnetized AND produce a field...

would that field be orthogonal as I think? what would be the interaction with the field of the solenoid? Somehow I can't figure this clearly (I have a sinusitis actually, which could play a role ;) )
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Signification
Tue Mar 17 2015, 04:13PM
Signification Registered Member #54278 Joined: Sat Jan 17 2015, 04:42AM
Location: Amite, La.
Posts: 367
Uspring wrote ...

I've found some sort of a proof for that the term I * dL/dt contains the complete backEMF.

Is the proof you found on the web? If so could you reference the link,
thanks
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Uspring
Tue Mar 17 2015, 04:36PM
Uspring Registered Member #3988 Joined: Thu Jul 07 2011, 03:25PM
Location:
Posts: 711
@Sig: No, painful own calculation.

@Shrad:
would that field be orthogonal as I think? what would be the interaction with the field of the solenoid?
Think of a simple loop of wire carrying a current. It will experience a force trying to widen it. This is a special case of the general rule, that the forces try to increase the inductance. Something similar happens to a solenoid. It will try to widen and also to become shorter. Both of these also would increase inductance. Same thing with a piece of iron near the coil. It will be sucked into it and therefore also increases inductance.

If you have a piece of iron, which at the same time will change the number of turns, if moved, two forces appear:
One force will suck the piece of iron into larger B fields, i.e. into the coil. The other force will try to increase inductance by lengthening the coil. That will be a force in the opposite direction. The forces won't necessarily cancel, but the larger force will be weakened.

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Shrad
Sat Mar 21 2015, 05:10PM
Shrad Registered Member #3215 Joined: Sun Sept 19 2010, 08:42PM
Location:
Posts: 780
as I understand it then the moving short would also reduce the coil mechanical stresses, right?
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