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4hv.org :: Forums :: High Voltage
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Parallel connected CCFLs

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Conundrum
Sun Nov 26 2006, 02:17AM Print
Conundrum Registered Member #96 Joined: Thu Feb 09 2006, 05:37PM
Location: CI, Earth
Posts: 4059
Hi all.

For your information, I found out how to parallel CCFL units so the outputs add together, generating 2000+V at several hundred mA to an amp.

The trick is to connect 120 ohm resistor between the "low" (i.e. Gnd) side of the HV transformer to the main ground, then diode on HV output.

I had five working at once and so far they seem stable; without the resistors this does not work and the transistors fry.

Did the "hv sparkler" effect :)


-A
]1164507463_96_FT0_sparkler.avi[/file]
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Wilson
Sun Nov 26 2006, 05:18AM
Wilson Registered Member #78 Joined: Thu Feb 09 2006, 11:27AM
Location: Sydney, Australia
Posts: 133
Did u just arc it to a regular sparkler? -__-'
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...
Sun Nov 26 2006, 05:41AM
... Registered Member #56 Joined: Thu Feb 09 2006, 05:02AM
Location: Southern Califorina, USA
Posts: 2445
Nope, bare copper does that when you give it enough power suprised
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ragnar
Sun Nov 26 2006, 08:27AM
ragnar Registered Member #63 Joined: Thu Feb 09 2006, 06:18AM
Location:
Posts: 1425
Bare steel does it even better. =P
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thedatastream
Sun Nov 26 2006, 09:47AM
thedatastream Registered Member #505 Joined: Sun Nov 19 2006, 06:42PM
Location: Yorkshire!
Posts: 329
Conundrum wrote ...

For your information, I found out how to parallel CCFL units so the outputs add together, generating 2000+V at several hundred mA to an amp.
...
I had five working at once and so far they seem stable; without the resistors this does not work and the transistors fry.
2000V * 700mA = 1.4kW? Are you sure?

Even if they are high power CCFL inverters, I would have thought that 10mA would have been a decent output current per inverter.

Better to use a series high voltage capacitor instead of a resistor because it is lossless. Select a value that gives you the reactance equivalent to the resistance you reqire using 1 / ( 2 * pi * f * C ). Ceramic cap for preference.

Not puting impedance in the inverter output will cause one inverter to try and supply more output current - too much and *pop* unless thre is some curent or power limit bult in to the control circuit.

Rgds,
James
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Marko
Sun Nov 26 2006, 10:21AM
Marko Registered Member #89 Joined: Thu Feb 09 2006, 02:40PM
Location: Zadar, Croatia
Posts: 3145
You can try using traditional 'or gate' made of diodes and connect it to ccfl's outputs. (shouldn't be too hard with 2kV

While system is weakly loaded only the ccfl with highest voltage output will be drained; others are blockd by it.

As load increases output voltage of first ccfl drops and this makes others come into use (system would be self-balancing).
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Conundrum
Sun Nov 26 2006, 02:54PM
Conundrum Registered Member #96 Joined: Thu Feb 09 2006, 05:37PM
Location: CI, Earth
Posts: 4059
Firkragg wrote ...

You can try using traditional 'or gate' made of diodes and connect it to ccfl's outputs. (shouldn't be too hard with 2kV

While system is weakly loaded only the ccfl with highest voltage output will be drained; others are blockd by it.

As load increases output voltage of first ccfl drops and this makes others come into use (system would be self-balancing).

"The trick is to connect 120 ohm resistor between the "low" (i.e. Gnd) side of the HV transformer to the main ground, then diode on HV output."

:)

-A

1164552848 96 FT18415 Ccfl 1
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