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Hacking memory cards

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Conundrum
Sat Mar 24 2012, 11:06AM Print
Conundrum Registered Member #96 Joined: Thu Feb 09 2006, 05:37PM
Location: CI, Earth
Posts: 4059
Hi all.
Just started another project, testing/diagnosing memory cards.

So far, I've built a USB test jig which reads the current drawn by the reader.
Tested with 3 cards.
Results below.
R = 18 ohms, to scale current to my meter's most sensitive range.
With 256MB xD
Quiescent = 0.787V
Reading is between 0.804V and 0.847V
Writing is between 1.051V and 1.074V

With 2GB xD
Quiescent = 0.847V
Reading is around 0.946mA
Writing is between 1.270V and 1.294V

With 32MB (!) MMC
Initial current = 0.781V
Quiescent = 0.994V when just accessed
Reading is between 1.153V and 1.174V
Writing is between 1.417V and 1.449V

To get actual current, subtract the reader's own current draw i.e. 0.715V from these readings.
Then divide by 18.0 to get the exact current used by the card(s).
From this you can see that the larger cards draw more power than the smaller ones.

This would also be an effective way to measure the number of layers in a given card, when its capacity is known.
A 4GB uSD would have 2 chips layered whereas a 32GB would have 17 or 9 depending on its technology.
As all the chip buffers need to be powered this would also let you locate a bad card or a FakeFlash.

Comments?
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Patrick
Tue Mar 27 2012, 03:29AM
Patrick Registered Member #2431 Joined: Tue Oct 13 2009, 09:47PM
Location: Chico, CA. USA
Posts: 5639
Conundrum wrote ...



...To get actual current, subtract the reader's own current draw i.e. 0.715V from these readings.
Then divide by 18.0 to get the exact current used by the card(s)...


can you explain this further? im not folowing your logic here.
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Steve Conner
Tue Mar 27 2012, 10:58AM
Steve Conner Registered Member #30 Joined: Fri Feb 03 2006, 10:52AM
Location: Glasgow, Scotland
Posts: 6706
You're assuming that Conundrum used logic in the first place smile I don't see how the reader can work properly with 1.4V dropped off its supply rail.
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