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4hv.org :: Forums :: General Science and Electronics
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Will HV current flow to Earth via Capacitance in this scenario?

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ScottH
Sun Mar 12 2017, 07:57PM
ScottH Registered Member #61373 Joined: Sat Dec 17 2016, 01:45PM
Location: San Antonio, TX
Posts: 87
Hypothetical scenario: A man is standing on a rubber mat that has a dielectric strength of 100,000v. It is a thin mat, about 4mm thick (I don't know what kind of rubber that would be). He is planning to work on a tree ajacent to a 7,200v power line. The man, oddly enough, is not wearing any shoes or gloves, and he is using a tall extending aluminum ladder.

The ladder that the man is holding falls sideways and contacts the 7,200v power line. Remember, the man is still standing on the rubber mat that is over good Earth.

Now since it is a large AC current, will the man still get shocked or electrocuted through Capacitance with current flowing through him to Earth?

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dexter
Sun Mar 12 2017, 08:56PM
dexter Registered Member #42796 Joined: Mon Jan 13 2014, 06:34PM
Location:
Posts: 195
does the ladder is still on the mat? because if so the statement "Now since it is a large AC current" is invalid

as for the current flowing through the capacitor can easily be calculated
calculate the capacitance, calculate the impedance and you'll have the current flowing through the man

my guess is the capacitor is in the pf range which means the impedance is in the GΩ rage and the current is a few micro amps
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Hydron
Sun Mar 12 2017, 09:57PM
Hydron Registered Member #30656 Joined: Tue Jul 30 2013, 02:40AM
Location: UK
Posts: 208
I have stood a couple of meters below a wire energised to 127kV @ 50Hz (note 127kV line-gnd = 220kV line-line).

Could definitely feel a tingle from the displacement current!

As mentioned above, why don't you make an approximation as to the area in contact with the mat (be generous) and a ballpark dielectric constant for rubber, then use the parallel plate capacitor calculation to work out capacitance to ground.

From this you'll be able to get a rough idea of what current would flow at whatever voltage/freq you'd like!
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ScottH
Sun Mar 12 2017, 11:47PM
ScottH Registered Member #61373 Joined: Sat Dec 17 2016, 01:45PM
Location: San Antonio, TX
Posts: 87
dexter wrote ...

does the ladder is still on the mat? because if so the statement "Now since it is a large AC current" is invalid

as for the current flowing through the capacitor can easily be calculated
calculate the capacitance, calculate the impedance and you'll have the current flowing through the man

my guess is the capacitor is in the pf range which means the impedance is in the GΩ rage and the current is a few micro amps


He's holding it off of the ground to place it.

Hydron wrote ...

I have stood a couple of meters below a wire energised to 127kV @ 50Hz (note 127kV line-gnd = 220kV line-line).

Could definitely feel a tingle from the displacement current!

As mentioned above, why don't you make an approximation as to the area in contact with the mat (be generous) and a ballpark dielectric constant for rubber, then use the parallel plate capacitor calculation to work out capacitance to ground.

From this you'll be able to get a rough idea of what current would flow at whatever voltage/freq you'd like!

Contact area is 60 Sq in. for both feet. In this scenario, dielectric of mat is 3 and current is 60hz. The mat is 4mm thick.

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Sulaiman
Mon Mar 13 2017, 11:31AM
Sulaiman Registered Member #162 Joined: Mon Feb 13 2006, 10:25AM
Location: United Kingdom
Posts: 3140
the effective area of the capacitor formed by the rubber mat to earth, will be quite large
as urine is conductive.
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Blackcurrant
Mon Mar 13 2017, 03:30PM
Blackcurrant Registered Member #2989 Joined: Sun Jul 11 2010, 12:01AM
Location: UK
Posts: 94
That's why they call it earth leakage testing
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radiotech
Tue Mar 14 2017, 05:27AM
radiotech Registered Member #2463 Joined: Wed Nov 11 2009, 03:49AM
Location:
Posts: 1546
You need the dielectric constant of the mat. Then the area of his two feet.Then the thickness of the mat.
Now get the capacity of the capacitor. Then the Xc.

Divide that into 7200. that will give you the current.




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dexter
Tue Mar 14 2017, 05:32PM
dexter Registered Member #42796 Joined: Mon Jan 13 2014, 06:34PM
Location:
Posts: 195
does the ladder is still on the mat? because if so the statement "Now since it is a large AC current" is invalid

as for the current flowing through the capacitor can easily be calculated
calculate the capacitance, calculate the impedance and you'll have the current flowing through the man

my guess is the capacitor is in the pf range which means the impedance is in the GΩ rage and the current is a few micro amps
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