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4hv.org :: Forums :: Tesla Coils
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Need advice on this slayer circuit

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jdub1581hv
Wed Jul 22 2015, 02:39PM
jdub1581hv Registered Member #55219 Joined: Tue Jun 09 2015, 11:21PM
Location:
Posts: 80
So I have been using this slayer circuit:

2- TIP3055 paralleled

It works well and quite well with my setup. The transistors only heat up when long duration arcs are pulled.
Gives my coil about 1" bushy ball like outbreak.

So I started playing with my circuit simulator (I know it doesn't always work in the real world) modifying the circuit.

I was hoping if anyone can tell me if this looks right (last image).. Cap and ground on secondary represent the top load.
I also set the transformer values as close to mine as possible including coupling at 0.2.

Basically the same as Image 1, with the added PNP, and a Cap across the primary.
Was hoping for review Before I build this and possibly blow up my transistors.
Transistors I have for this are TIP3055, TIP42G .





1437575941 55219 FT0 Simpleslayer

1437575941 55219 FT0 20150721 012639 Richtonehdr

1437575941 55219 FT0 Modifiedslayer
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jdub1581hv
Sat Jul 25 2015, 03:19AM
jdub1581hv Registered Member #55219 Joined: Tue Jun 09 2015, 11:21PM
Location:
Posts: 80
No one? nothing?
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Antonio
Sat Jul 25 2015, 02:07PM
Antonio Registered Member #834 Joined: Tue Jun 12 2007, 10:57PM
Location: Brazil
Posts: 644
The second will probably just destroy the PNP transistor. Test it with a current-limiting resistor in series with the primary.
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mister_rf
Sat Jul 25 2015, 06:51PM
mister_rf Registered Member #4465 Joined: Wed Apr 18 2012, 08:37AM
Location: Bucharest, Romania
Posts: 145
What Antonio is saying is you need to have a current limiting resistor in front of the base terminal on the transistor, which does exactly what its name describes, limits the current.
The base-emitter junction acts like any silicon diode (it’s the 'NP' part of the PNP transistor). For current to flow through the junction the base must be about 0.6V higher than the emitter.
The value of base resistor sets the size of base current. As the voltage drop across the transistor will remain at 0.6-0.8V we can work out the size resistor we would need quite easily.
R = (Vin - Vdrop)/I,
I = the base current that it can take, to force saturation
Vdrop = the voltage drop from the base to the emitter
Vin = the supply that is going into base
Also need to look at the hfe of the transistor so see if it will be able to give you the amount of current is needed.
In the attached picture Rb is simply a label and may have different values in different circuits. Let’s say Rb = 220 ohms up to 1k.




1437849441 4465 FT1630 Modifiedslayer
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jdub1581hv
Sat Jul 25 2015, 09:50PM
jdub1581hv Registered Member #55219 Joined: Tue Jun 09 2015, 11:21PM
Location:
Posts: 80
Thanks guys! My buddy I usually go to for help is out of town for a few months for work.
He actually got me into the electronics side of electricity.. lol.

I knew there would be a problem with the PNP, as in the sim the tank cap was reaching towards the sky in terms of wattage.


So for "Rb" say I put a 220ohm followed by a 1k pot this should allow for some mediocre tuning?
I'm using a 9v battery to check my circuits so nothing goes boom.

I also have a few TIP107 pnp darlingtons with 1k to 20k hfe
8amp tolerance at collector and 1a at base..
I'll try these as well, and post an update.

Now I just need to get a good psu. as my 75va 22v xfmr gets stressed a bit..

This was where I took the idea from: (mixing the two)

2n2222

1437861005 55219 FT172292 3055t
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mister_rf
Sun Jul 26 2015, 05:13AM
mister_rf Registered Member #4465 Joined: Wed Apr 18 2012, 08:37AM
Location: Bucharest, Romania
Posts: 145
If you are using the TIP107, there's no need for the 1k resistor, because that PNP darlington transistor already has the Base-Emitter shunt resistors.



1437887458 4465 FT172292 Tip107
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