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Registered Member #4266
Joined: Fri Dec 16 2011, 03:15AM
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Posts: 874
1.28kg/m3 air density 1.01kj/kg/k 0.6C change in tempture over thrity years 71% abosation of energy 2.06e11 m3/1meter height/area of earth 1.6066e11kJ extra 1kw input averaged 1.09kw extra energy for 0.6
Does this mean, that to have a stable 0.6C rise, the sun would have to ouput twice the energy it did thrity years ago, and if it was costant, whats stopping the energy escaping, as 2.09kw/1kw has the same vibrational and convection heat transfer modes? 0.024w/m/k for air 0.0146 for CO2
0.0146*0.6C = 0.00876ratio 0.00876/0.024 = 0.365 which is about 40% increase of CO2, which match current levels of 380ppm, but if theres 0.365kW/m for just air, does thatean the sun is ouputing a extra 365watts*71% absoation rate than it did thrity years ago Thanks
Registered Member #72
Joined: Thu Feb 09 2006, 08:29AM
Location: UK St. Albans
Posts: 1659
Let's check your assumptions, before checking your detailed figures.
You're assuming that all the heat is stored in the atmosphere, uniformly, and none is coupled to the shallow or deep ocean, and there is no contribution from latent heat for ice, water and vapour, and the surface and cloud albedo remains constant?
Registered Member #4266
Joined: Fri Dec 16 2011, 03:15AM
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I dont think that paths the right way to take, as there are tomany varabiles, instead of looking back, im taking the output value of the system and focusing on the ouput part from surface level of land and sea, too one meterabove, and assuming that above what ever there micro systems are has produced the 0.6C change on average of thrity years.
It's hard to follow, what you are calculating, since you just post numbers and not the quantities or equations you use. My impression is, that you want to calculate the temperature rise based on the specific heat capacity of the atmosphere due to the incoming radiation power. Let me do this:
Mass M of air per m^2 of the atmosphere: About 10000 kg. Specific energy capacity c of air: about 1kJ/kg/K Sun power P per m^2: about 1.4 kW The rate of heating is then: R = P/(c*M) = 1.4*10^-4 K/s.
For a day of sunshine (40000s), that would amount to about 6K. The earth, of course, doesn't heat up at that rate continuously, since it radiates almost all the energy back into space. The heating up of the earth can only be understood by considering its energy reflection properties.
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Can someone check my numbers on raditive heating.
